Could someone answer this and explain an easier way to do this?

Mathematics

1 answer:

goblinko [34]2 years ago

3 0

Answer:

Area of the figure = 109 cm. square

Step-by-step explanation:

The radius of the semi circle is 12 ÷ 2 = 6 cm.

Area of the semi circle = $\frac{1}{2}\pi(6^{2})=18\pi$

The radius of the quarter circle is 6 cm.

Area of the quarter circle = $\frac{1}{4}\pi(6^{2}=9\pi$

The area of the rectangle = 12 × 2 = 24

The area of the figure = 18π + 9π + 24 = 108.78 ≅ 109 cm. square

You might be interested in

Which relation is a function?

Ksivusya [100]

B. To see if it’s a function, it has to pass the vertical line test. That means draw a vertical line (going up and down) through any point on the graph and it can only go through one point. If it goes through more than 1, it’s not a function. Like in graph A, if you draw a vertical line at x=-2, it will go through two points, same at x=2. For graph b, no matter where you move a vertical line, it only passes through one point at a time, so it passes the vertical line test.

8 0

2 years ago

Y=3x-2<br> Y=2x-5<br> Find X and Y using substitution

tiny-mole [99]

$y = 3x -2~~~.....(i)\\\\y = 2x-5~~~.....(ii)\\\\\text{Substitute equation (i) in equation (ii):}\\\\3x-2 = 2x -5\\\\\implies 3x -2x = -5+2\\\\\implies x = -3\\\\\text{Substitute}~ x =-3,~ \text{in equation (i):}\\\\y = 3(-3) -2 = -9 -2 = -11\\\\\text{Hence,}~ (x,y) = (-3,-11)$