Using the z-distribution, as we are working with a proportion, it is found that 1016 constituents are required.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
is the sample proportion.
The margin of error is given by:
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.96.
The estimate is of 
, while the margin of error is of M = 0.03, hence solving for n we find the minimum sample size.
Rounding up, 1016 constituents are required.
More can be learned about the z-distribution at brainly.com/question/25890103
Answer:
38
Step-by-step explanation:
38
Answer:
A
Step-by-step explanation:
Answer:
Step-by-step explanation:
When we take an average of something, we have to add up all the data on the somethings and then divide by the number of somethings we have. Ed takes 5 tests, and we have scores for them; we also have his current average. What we don't know for sure are 2 of the 5 test scores, but we have enough to determine what they are.
If one test has a score of x, and the other test is 3 points less than that, the score on that last test is x - 3. Putting all of that together into an average problem:
and simplfiying a bit:
. Multiply both sides by 5 to get
256 + 2x = 450; subtract 256 from both sides to get
2x = 194 and divide by 2:
x = 97
The one test score was a 97 and the other one, which was 3 less than that, was a 94.
Answer: 3
Step-by-step explanation:
By the intersecting chords theorem,
