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Katyanochek1 [597]
3 years ago
7

A spring has a spring constant of 256 n/m. how far must it be stretched to give it an elastic potential energy of 48 j?

Physics
1 answer:
pychu [463]3 years ago
4 0
Elastic potential energy=1/2kx^2 (k is constant and x is how far it has to be stretched. So 48=1/2(256)x^2 which is 0.6123
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Answer:

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Explanation:

Given:-

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