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Eva8 [605]
3 years ago
7

5. A new technique called adaptive optics allows astronomers to: a. change the eyepieces of their telescopes much more quickly t

han ever before b. compensate for changes in the Earth's atmosphere and achieve better resolution c. increase the aperture of their telescopes by connecting several telescopes d. change the region of the electro-magnetic spectrum in which their telescope is able to detect radiation e. use the observatory shop to make better eye-glasses for their graduate students
Physics
1 answer:
Yuliya22 [10]3 years ago
4 0

Answer:

b. compensate for changes in the Earth's atmosphere and achieve better resolution.

Explanation:

  • The adaptive optic is a technology that is used to enhance the application of optical system in reducing the impact from the incoming distractions.
  • It  is dine to reduce the optical abbrebrivation. It is also used for correcting the tip-tilt correction by using the segmented mirrors.
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The greenhouse effect that raises the surface temperature of planets
PSYCHO15rus [73]

Answer:

c

Explanation:

Green house effect:

 Temperature of atmosphere is going to  increased continuously, because infrared light absorbed by gas .This increased in temperature atmosphere    is called green house effect.

The green houses gases are as follows

,Carbon diaoxide,water vapor  ,,Carbon diaoxide ,Methane ,,Carbon diaoxide oxide,CFCs ,ozone.

So the option c is correct.

3 0
3 years ago
Steve want to catch up to Cami, a girl he likes. If he is jogging at 8 m/s and she is walking at 1 m/s. How long will it take hi
Aleks04 [339]

Answer:

<u><em>1) if they are moving away from each other it will take 1.43 secs</em></u>

<u><em>2) if they are moving towards each other then it will take 1.11 secs</em></u>

Explanation:

Distance between them is 10 m

Speed  ( if they are moving towards each other)= distance/time

time = 10/8+1

time = distance / speed= 10/9=  1.11 secs

if they are moving away from each other than it will take

time = 10/8-1= 10/7= 1.43 secs

5 0
3 years ago
A compact disc (CD) stores music in a coded pattern of tiny pits 10−7m deep. The pits are arranged in a track that spirals outwa
andreev551 [17]

(a) 50 rad/s

The angular speed of the CD is related to the linear speed by:

\omega=\frac{v}{r}

where

\omega is the angular speed

v is the linear speed

r is the distance from the centre of the CD

When scanning the innermost part of the track, we have

v = 1.25 m/s

r = 25.0 mm = 0.025 m

Therefore, the angular speed is

\omega=\frac{1.25 m/s}{0.025 m}=50 rad/s

(b) 21.6 rad/s

As in part a, the angular speed of the CD is given by

\omega=\frac{v}{r}

When scanning the outermost part of the track, we have

v = 1.25 m/s

r = 58.0 mm = 0.058 m

Therefore, the angular speed is

\omega=\frac{1.25 m/s}{0.058 m}=21.6 rad/s

(c) 5550 m

The maximum playing time of the CD is

t =74.0 min \cdot 60 s/min = 4,440 s

And we know that the linear speed of the track is

v = 1.25 m/s

If the track were stretched out in a straight line, then we would have a uniform motion, therefore the total length of the track would be:

d=vt=(1.25 m/s)(4,440 s)=5,550 m

(d) -6.4\cdot 10^{-3} rad/s^2

The angular acceleration of the CD is given by

\alpha = \frac{\omega_f - \omega_i}{t}

where

\omega_f = 21.6 rad/s is the final angular speed (when the CD is scanned at the outermost part)

\omega_i = 50.0 rad/s is the initial angular speed (when the CD is scanned at the innermost part)

t=4440 s is the time elapsed

Substituting into the equation, we find

\alpha=\frac{21.6 rad/s-50.0 rad/s}{4440 s}=-6.4\cdot 10^{-3} rad/s^2

5 0
4 years ago
Read 2 more answers
A sled and rider (combined mass of 69 kg) finish a downhill run with a speed of 30 m/s, then enter a flat (horizontal) area wher
NARA [144]

Answer:

Distance that sled move while slowing down= 195.65m

Explanation:

Distance traveled by sled after slowing down=S

acceleration at the start= -2.3 m/s2

initial speed u=30m/s

final speed=v

By using the equation

v^{2} =u^{2} +2as\\

Final speed is zero.

Therefore;

0=30^{2} +2*(-2.3)*s\\2*2.3s=30^{2} \\s=30^{2} /(2*2.3)\\s=195.65 m

6 0
4 years ago
Ivan exerts 20 N of force to lift a basket 2 m. He then carries the basket 5 m across a room to place it on a shelf. Ivan does w
amid [387]
A) <span>Ivan does work when he lifts the basket

B) Work = Force * displacement 
W = 20 * 2
W = 40 Joules

So, The Amount of work he does is 40 Joules

Hope this helps!</span>
7 0
3 years ago
Read 2 more answers
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