Answer:
Explanation:
given,
charge of two spherical drop = 0.1 nC
potential at the surface = 300 V
two drops merge to form a single drop
potential at the surface of new drop = ?
r = 0.003 m
volume = 
= 
= 2.612 × 10⁻⁷ m³
![R =\sqrt[3]{\dfrac{2.612 \times 10^{-7}\times 3}{4\times \pi}}](https://tex.z-dn.net/?f=R%20%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B2.612%20%5Ctimes%2010%5E%7B-7%7D%5Ctimes%203%7D%7B4%5Ctimes%20%5Cpi%7D%7D)
R = 0.00396 m
1) Horizontal velocity, Vx
Vx is constant and equal to 5.0 m/s
The graph Vx(t) = 5.0 m/s is a horizontal line (parallel to the horizontal t-axis). that intercepts the vertical-axis at 5.0 and runs from t = 0 to t = 2.
2) Vertical velocity, Vy
Vy = gt = 10t
d = at^2 / 2 => tmax = √(2d / a) = √(2*20m/10m/s^2) = 2 s
Graph Vy is an inclined line with slope 10 m/s^2, that runs from t =0 to t = 2 s, and passes through the points (0,0), (1,10), and (2,20).
The momentum<span> of a particle is defined as the product of its mass times its velocity. It is a vector quantity. Therefore, the momentum of the baseball would be as follows:
Momentum = mass x velocity
Momentum = 0.45 kg (25 m/s)
Momentum = 11.25 kg m/s</span>
The object with the lighter mass will accelerate more
Around 3.70 seconds unless traveling through media
