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zavuch27 [327]
3 years ago
9

Consider the gravity of the four spheres. If we wanted sphere C to attract the other three spheres, what is one feature of spher

e C we must change?
A) Increase its mass.
B) Make it less dense.
C) Increase its diameter.
D) Change its composition.
Physics
2 answers:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

B

Explanation:

otez555 [7]3 years ago
4 0

Answer:

The correct answer is A.

Explanation:

A greater mass means a greater gravitational pull. To give Sphere C more gravitational pull you mus increase its mass

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A student drops an object out the window of the top floor of a high-rise dormitory.
seropon [69]

-- The acceleration due to gravity is 32.2 ft/sec² .  That  means that the
speed of a falling object increases by an additional 32.2 ft/sec every second.

-- If dropped from "rest" (zero initial speed), then after falling for 4 seconds,
the object's speed is (4.0) x (32.2) = <em>128.8 ft/sec</em>.

-- 128.8 ft/sec = <em>87.8 miles per hour</em>

Now we can switch over to the metric system, where the acceleration
due to gravity is typically rounded to 9.8 meters/sec² .

-- Distance = (1/2) x (acceleration) x (time)²

       D = (1/2) (9.8) x (4)² =<em>  78.4 meters</em>

-- At 32 floors per 100 meters,  78.4 meters = dropped from the <em>25th floor</em>.


The 5 points are certainly appreciated, but I do wish they were Celsius points.


3 0
3 years ago
The electron affinity of thulium has been measured by a technique known as laser photodetachment electron spectroscopy. In this
antoniya [11.8K]

Answer:

ΔE = 1.031 eV

Explanation:

For this exercise let's calculate the energy of the photons using Planck's equation

          E = h f

wavelength and frequency are related

         c = λ f

         f = c /λ

let's substitute

         E = h c /λ

let's calculate

         E = 6.63 10⁻³⁴ 3 10⁸/1064 10⁻⁹

         E = 1.869 10⁻¹⁹ J

let's reduce to eV

         E = 1.869 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

        E = 1.168 eV

therefore the electron affinity is

         ΔE = E - 0.137

         ΔE = 1.168 - 0.137

         ΔE = 1.031 eV

3 0
3 years ago
What does the dashes line represent
Yuki888 [10]
 dashed lines<span> represent bonds away from the viewer.</span>
3 0
3 years ago
The low pressure area near Earth's equator is filled by cool air moving in from
Rainbow [258]
The answer is A! Europe and South America
5 0
2 years ago
If the net external torque acting on the particle is zero, the it satisfies - 1st condition of equilibrium - 2nd condition of eq
Marizza181 [45]

Answer:

a) the distances are zero, Both 1st & 2nd condition

c)  the torques are equal but of the opposite sign, 2nd condition of equilibrium

Explanation:

The equilibrium conditions are

1 translational

        ∑ F = 0

2 rotational

        ∑ τ = Σ (F_i x r_i) = 0

They tell us that external torque is zero.

Therefore we have two various possibilities

a) the distances are zero, in this case we have a pure translation movement

    for this situation the two equilibrium relations are fulfilled

b) the forces are zero, there is no movement

    It does not make sense to use the equilibrium relations since there are no forces

c) the torques are equal but of the opposite sign, the forces are on the opposite side of the body.

    In this case the 2 equilibrium relation is fulfilled, but not the first one that the force has the same direction

7 0
3 years ago
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