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Sedaia [141]
3 years ago
6

In this assignment, you will use your knowledge of

Biology
2 answers:
dimulka [17.4K]3 years ago
6 0

Answer:

Control of body’s internal environment to maintain ‘homeostasis’.

Programming of spinal cord reflexes.

Memory and learning.

Voluntary control of movement.

Explanation:

Ahat [919]3 years ago
5 0

Answer: We have two parts working for our central nervous system. The brain: it serves as the main control of the human body, it receives information from our senses and provides reaction. The spinal cord: this play a vital role to distribute all neurons throughout, it serves as a connection to provide transmission. processes information from receptors that detect changes in the environments ends out appropriate responses to react to changes in the environment maintains homeostasis for the body coordinates all systems of the body serves as an information highway for the body by sending and receiving messages answer on e2020

Explanation:

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\bf \huge \red{F} \bf \pink{O}\bf \purple{L}\bf \blue{L}\bf \green{O}\bf \red{W} \: \bf \pink{x} \bf \purple{I} \bf \blue{t} \bf \green{z} \bf \red{M} \bf \pink{u} \bf \purple{s} \bf \blue{k} \bf \green{x}

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8 0
4 years ago
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You cross two true-breeding parents (one with yellow seeds and one with green seeds), grow and self-pollinate the F1 generation,
Andru [333]

Answer:

1500

Explanation:

Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.

The total population size of F2 generation = 2000

The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)

Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500

3 0
3 years ago
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