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enyata [817]
3 years ago
11

Camila and her children went into a grocery store and where they sell apples for $0.50 each and mangos for $0.75 each. Camila ha

s $7.75 to spend and must buy no less than 11 apples and mangos altogether. If Camila decided to buy 8 apples, determine the maximum number of mangos that she could buy. If there are no possible solutions, submit an empty answer
Mathematics
1 answer:
german3 years ago
8 0

Maximum number of mangoes that Camila can buy are 5

Step-by-step explanation:

  • Step 1: Find the cost of 8 apples bought by Camila.

Cost of 1 apple = $0.50

Cost of 8 apples = $0.50 × 8 = $4

  • Step 2: Find the remaining amount with Camila after she bought 8 apples.

Total amount that can be spent = $7.75

Cost of apples = $4

Remaining amount = $7.75 - $4 = $3.75

  • Step 3: Find the number of mangoes she can buy

Cost of 1 mango = $0.75

Number of mangoes = $3.75/$0.75 = 5

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Step-by-step explanation:

(y2-y1)/(x2-x1)

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Then plug one of the coordinates into y = -3x+b to get b

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3 years ago
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tiny-mole [99]

Ok, so the question is based on geometric progression. Remember, the formula for calculating the nth-term of a geometric progression is: a*r^{n-1}. The a in the expression stands for the 1st term of the sequence, and r is the common ratio of the elements of the sequence. Now let's take a look at the problem.

"A ping pong ball has a 75% rebound ration". We can infer that our common ratio, r, is 75% which is 0.75.

"When you drop it from a height of k feet...", this means the first height you drop it from, a.k.a, the first term.

Now going back to the expression, the nth-term = a*r^{n-1}, we can substitute our common ration, 0.75 with r, and our 1st term, k, with a. This becomes: k * 0.75^{n-1}. This becomes our expression.

a. The highest height achieved by the ball after six bounces. Our nth-term here is 6, so let's use our expression to find the 6th term. n_{6} = 235 * 0.75^{6-1} = 235*0.75^{5} = 235*0.2373 = 55.7655ft

b. The total distance travelled by the ball when it strikes the ground for the 12th time. This involves the use of the sum of elements in the geometric progression. The formula for that is \frac{a(1 - r^{n})}{1-r}, provided that r is less than 1, which it is in this case, since 0.75 is less than one. Our nth-term here is 12, so we substitute.

\frac{235(1-0.75^{12})}{(1-0.75)} = 910.2242ft

6 0
3 years ago
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Answer:

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3 * 13,600 / 100 = $408

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3 years ago
Find the product of all positive divisors of 288.
irinina [24]

Answer:

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>.</em><em>5</em><em>1</em><em>4</em><em>5</em><em>7</em><em>1</em><em>8</em><em>9</em><em>4</em><em>×</em><em>1</em><em>0</em><em>^</em><em>2</em><em>1</em><em>.</em>

Step-by-step explanation:

<em>Here</em><em>, </em><em> </em><em>the</em><em> </em><em>divisors</em><em> </em><em>of</em><em> </em><em>2</em><em>8</em><em>8</em><em> </em><em>are</em><em>,</em>

<em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>6</em><em>,</em><em>8</em><em>,</em><em>9</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>6</em><em>,</em><em>1</em><em>8</em><em>,</em><em>2</em><em>4</em><em>,</em><em>3</em><em>2</em><em>,</em><em>3</em><em>6</em><em>,</em><em>4</em><em>8</em><em>,</em><em>7</em><em>2</em><em>,</em><em>9</em><em>6</em><em>,</em><em>1</em><em>4</em><em>4</em><em>,</em><em>2</em><em>8</em><em>8</em><em>.</em>

<em>now</em><em>,</em><em> </em><em>their</em><em> </em><em>product</em><em> </em><em>=</em><em>1</em><em>×</em><em>2</em><em>×</em><em>3</em><em>×</em><em>4</em><em>×</em><em>6</em><em>×</em><em>8</em><em>×</em><em>9</em><em>×</em><em>1</em><em>2</em><em>×</em><em>1</em><em>6</em><em>×</em><em>1</em><em>8</em><em>×</em><em>2</em><em>4</em><em>×</em><em>3</em><em>2</em><em>×</em><em>3</em><em>6</em><em>×</em><em>4</em><em>8</em><em>×</em><em>7</em><em>2</em><em>×</em><em>9</em><em>6</em><em>×</em><em>1</em><em>4</em><em>4</em><em>×</em><em>2</em><em>8</em><em>8</em>

<em>=</em><em>1</em><em>.</em><em>5</em><em>1</em><em>4</em><em>5</em><em>7</em><em>1</em><em>8</em><em>9</em><em>4</em><em>×</em><em>1</em><em>0</em><em>^</em><em>2</em><em>1</em><em>.</em>

<em>is</em><em> </em><em>answer</em><em>. </em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
3 years ago
Read 2 more answers
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