Answer:
square root of 49
Step-by-step explanation:
square root of 2 is 1.41421356237
square root of 14 is 3.74165738677
square root of 49 is 7
square foot of 49 is the correct one because 6.27316543222718… keeps going and does not stop the other 2 is irrational and square root of 49 is 7 basically meaning is rational
Hope this helped! :)
May i have brainliest!
Answer:
(D) 30pi inches
Step-by-step explanation:
First, we use the given volume, the given height, and the formula of the volume of a cylinder to find the radius of the base. Then we use the radius of the base to find the circumference of the base.
![volume = \pi r^2 h](https://tex.z-dn.net/?f=%20volume%20%3D%20%5Cpi%20r%5E2%20h%20)
![volume = 6750 \pi~in.^3](https://tex.z-dn.net/?f=%20volume%20%3D%206750%20%5Cpi~in.%5E3%20)
We set the formula equal to the volume and replace h with 30 in.
![\pi r^2 h = 6750 \pi~in.^3](https://tex.z-dn.net/?f=%20%5Cpi%20r%5E2%20h%20%3D%206750%20%5Cpi~in.%5E3%20)
![\pi r^2 \times 30 ~in. = 6750 \pi~in.^3](https://tex.z-dn.net/?f=%20%5Cpi%20r%5E2%20%5Ctimes%2030%20~in.%20%3D%206750%20%5Cpi~in.%5E3%20)
Divide both sides by 30pi in.
![r^2 = 225 ~in.^2](https://tex.z-dn.net/?f=%20r%5E2%20%3D%20225%20~in.%5E2%20)
Take the square root of each side.
![\sqrt{r^2} = \sqrt{225 ~in.^2}](https://tex.z-dn.net/?f=%20%5Csqrt%7Br%5E2%7D%20%3D%20%5Csqrt%7B225%20~in.%5E2%7D%20)
![r = 15~in.](https://tex.z-dn.net/?f=%20r%20%3D%2015~in.%20)
The radius of the base is 15 in.
Now we use the radius of the base and the formula of the circumference of a circle to find the answer.
![circumference = 2 \pi r](https://tex.z-dn.net/?f=%20circumference%20%3D%202%20%5Cpi%20r%20)
![circumference = 2 \pi \times 15~in.](https://tex.z-dn.net/?f=%20circumference%20%3D%202%20%5Cpi%20%5Ctimes%2015~in.%20)
![circumference = 30 \pi ~in.](https://tex.z-dn.net/?f=%20circumference%20%3D%2030%20%5Cpi%20~in.%20)
Answer:6/4
Step-by-step explanation:
For this case we must algebraically rewrite the given expression. So:
x: It is the variable that represents an unknown number
"double a number" is represented as: ![2x](https://tex.z-dn.net/?f=2x)
"6 less than double a number" is represented as: ![2x-6](https://tex.z-dn.net/?f=2x-6)
So, the final expression is: ![2x-6](https://tex.z-dn.net/?f=2x-6)
If we want to rewrite the expression in an equivalent way, we take common factor 2:
![2 (x-3)](https://tex.z-dn.net/?f=2%20%28x-3%29)
Asnwer:
![2x-6](https://tex.z-dn.net/?f=2x-6)
Equivalent expression: ![2 (x-3)](https://tex.z-dn.net/?f=2%20%28x-3%29)
Answer:
x = 0
Step-by-step explanation:
the origin