Answer:
1) ![5^2=25](https://tex.z-dn.net/?f=5%5E2%3D25)
2) ![5^2=x](https://tex.z-dn.net/?f=5%5E2%3Dx)
3) ![b^3=64](https://tex.z-dn.net/?f=b%5E3%3D64)
Step-by-step explanation:
To write logs of the form
in their exponential form, you take the base b and put it to the power of x and then set that equal to a:
.
1. Here, b = 5, a = 25, and x = 2, so: ![5^2=25](https://tex.z-dn.net/?f=5%5E2%3D25)
2. In this problem, b = 5, x = 2, and a = x, so: ![5^2=x](https://tex.z-dn.net/?f=5%5E2%3Dx)
3. Finally, here, b = b, a = 64, and x = 3, so: ![b^3=64](https://tex.z-dn.net/?f=b%5E3%3D64)
Hope this helps!
Answer:
The answer is D.
Step-by-step explanation:
In order to find how many times human blink more than the blink of a dig, you have to divide it :
![9460800 \div 1861440](https://tex.z-dn.net/?f=9460800%20%5Cdiv%201861440)
![= 5 \: times](https://tex.z-dn.net/?f=%20%3D%205%20%5C%3A%20times)
Answer:
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
gradient for the line y=5x+2 = 5 from y=mx+c where m =gradient
parallel lines have equal gradients thus M2=5
equation for line passing through point (-6,-1) and gradient , m=5 will be
(change in y/change in x)=M2
(y--1/x--6)=5
y+1/x+6 =5
y+1=5(x+6)
y+1=5x+30
y=5x+29