A.)
Z = kx/y where k is a constant.
32 = 16k/4
k = 128/16
k = 8
z = 8x/y
b.)
Z = 8(21)/6
Z = 28
c.)
4 = 8x/48
x = 192/8
x = 24
Answer: The amount of carbon-14 remaining after 4 years is 99.95 grams.
Step-by-step explanation:
Hi, to answer this question we simply have to substitute t=4 in the equation given and solve for c.
c= 100 (0.99988)^t
c =100 (0.99988)^4
c = 100 x 0.999520086
c= 99.95200864 ≅99.95 grams (rounded)
The amount of carbon-14 remaining after 4 years is 99.95 grams.
Feel free to ask for more if needed or if you did not understand something.
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