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True [87]
2 years ago
15

Each square in Figures D and E has a side length of 1 unit. Compare the area of the two figures. Which figure has more area? How

much more? Explain or show your reasoning.

Mathematics
1 answer:
dsp732 years ago
4 0

Option B has more, if you want to have mathematical work just set each of the square side lengths to 1. In the first figure, you have 4 units square for each square so 2 units sq on the first and 4 on the second. Then since the other shapes are half circles or 1/4 circles we can put them together to get full and partial circles. The first shape had 2 full circles and the second shape has 1.5. SO using 1 as the radius, you get 3.14 units sq per circle. Leaving you with (<em>circles) </em>6.28 + <em>(squares)</em> 2 leaving you with 8.28 units sq for figure 1 and <em>(circles)</em> 4.71  + <em>(squares)</em> 4 leaving you with 8.71 for figure 2. This leaves you with a .43 difference. Hope this helps

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When temperature is zero degree Celsius, the Fahrenheit temperature is 32. When the Celsius temperature is 100, the correspondin
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Answer:

\\ y = 1.8(x) + 32 or \\ y = \frac{9}{5}(x) + 32

or equivalently:

\\ F = 1.8(C) + 32 or \\ F = \frac{9}{5}(C) + 32

Step-by-step explanation:

To express the Fahrenheit temperature <em>as a linear function of the Celsius temperature</em>, F(c), we can proceed as follows.

We can use here <em>the two-point form</em> <em>equation</em> of a line:

\\ y-y_1 = \frac{y_2 - y_1}{x_2 - x_1}(x-x_1) [1]

We are asked to express the <em>Fahrenheit temperature</em> as a function of <em>Celsius temperature</em>, so the independent variable, in this case, is <em>x</em> (Celsius temperature) and the dependent variable is <em>y</em> (Fahrenheit temperature).

When temperature is zero degree Celsius (\\x_1 = 0), the Fahrenheit temperature is 32 (\\y_1 = 32).

When the Celsius temperature is 100 (\\x_2 = 100), the corresponding Fahrenheit temperature is 212 (\\y_2 = 212).

Then, using [1], we have:

\\ y-32 = \frac{212 - 32}{100 - 0}(x-0)

\\ y-32 = \frac{180}{100}(x)

\\ y-32 = 1.8(x).

It could be also be written as:

\\ y-32 = \frac{18}{10}(x) = \\ y-32 = \frac{9}{5}(x), as it commonly appears in books.

Then <em>the Fahrenheit temperature express as a linear function of the Celsius temperature, F(c</em>) is ( solving the equation for <em>y </em>) :

\\ y = 1.8(x) + 32 or \\ y = \frac{9}{5}(x) + 32.

Or equivalently:

\\ F = 1.8(C) + 32 or \\ F = \frac{9}{5}(C) + 32

We can check this using the given values from the question:

For 0 Celsius degrees, the Fahrenheit temperature is:

\\ y = 1.8(0) + 32 = 32 Fahrenheit degrees.

For 100 Celsius degrees, the Fahrenheit temperature is:

\\ y = 1.8(100) + 32 = 180 + 32 = 212 Fahrenheit degrees.

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Answer:

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z = -3

Step-by-step explanation:

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