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noname [10]
3 years ago
13

Suppose that IQ scores in one region are normally distributed with a standard deviation of . Suppose also that exactly of the in

dividuals from this region have IQ scores of greater than (and that do not). What is the mean IQ score for this region
Mathematics
1 answer:
olga55 [171]3 years ago
7 0

Answer: Hello your question is poorly written attached below is the complete question

answer : 101.8

Step-by-step explanation:

Given data :

Standard deviation ( б ) = 14

55% have IQ scores > 100

45% have IQ scores < 100

<u>Determine the mean IQ score for the region</u>

P ( X > x ) =

P ( Z ≥ ( 100 - μ ) / 14 ) = 0.55    also

P ( Z ≤ ( 100 - μ ) / 14 ) = 0.45

<em>using standard normal calculator </em>

100 - μ  / 14  = Z₀.₄₅ = - 0.126

<em>resolving the relation above</em>

100 - μ  / 14  = - 0.126

μ = 100 - 14 ( -0.126 )

   = 101.764 ≈ 101.8

             

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Read 2 more answers
What is the domain and range of f(x)=2|x+2|-8
RideAnS [48]

Answer:

The domain of f(x) is {x : x ∈ R} and the range is {y : y ≥ -8}

Step-by-step explanation:

- The domain of the function is the values of x which make the

  function defined

- The rang is the corresponding values of y with the domain

- The parent function of f(x) is g(x) = IxI

- The graph of this function represented by 2 lines starting from  

  the origin, one of them with positive slope and the other with negative

  slope and both of them over the x-axis

- The Domain of g(x) is {x : x ∈ R} where R is the set of real numbers

- That mean the domain of g(x) is all real numbers

- The range of g(x) is {y : y ≥ 0}

- That mean the range is all real numbers greater than or equal to zero

- f(x) is the image of g(x) after some transformations

- g(x) multiplied by 2 that mean vertical stretch.

- Then x add by 2 that mean horizontal translation to the left by 2 units

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   x-axis and moved to the left 2 units and down 8 units

- That means the image of the origin is (-2 , -8)

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- The domain of f(x) is {x : x ∈ R}

- But the range changes is because the graph of the function starts

 from -8 not from 0

- Then the range of f(x) is {y : y ≥ -8}

* The domain of f(x) is {x : x ∈ R} and the range is {y : y ≥ -8}

- <em>Look to the attached graph for more understand</em>

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