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3 years ago

What rule is observed when naming an oxyacid that does have oxygen in its formula?

Chemistry

2 answers:

lesya692 [45]3 years ago

5 0

Answer:

An oxyacid with two less oxygen atoms than the (root)ic acid is named by writing hypo-, then the root of the name for the element other than hydrogen and oxygen, then -ous, and then acid. Therefore, HClO, is hypochlorous acid

Explanation:

Harman [31]3 years ago

4 0

Answer:

Anion name and Acid name

Formula Anion Anion name Acid Name

HF F- is fluoride hydrofluoric acid

HCl Cl- is chloride hydrochloric acid

HBr Br- is bromide hydrobromic acid

HI I

- is iodide hydroiodic acid

H2S S2- is sulfide hydrosulfic acid

HNO2 NO2 is nitrite nitrous acid

HNO3 NO3

is nitrate nitric acid

HC2H3O2 C2H3O2

is acetate acetic acid

H2SO4 SO4

2- is sulfate sulfuric acid

H2CO3 CO3

2- is carbonate carbonic acid

H3PO4 PO4

3- is phosphate phosphoric acid

HClO ClO¯ is hypoclorite hypochlorous acid

HClO2 ClO2¯ is chlorite chlorous acid

HClO3 ClO3¯ is chlorate chloric acid

HClO4 ClO4¯ is perchlorate perchloric acid

HIO3 IO3¯ is iodate iodic acid

HNO2 NO2¯ is nitrite nitrous acid

H2SO3 SO3

2- is sulfite sulforous acid

HCN CN is cyanide hydrocyanic acid

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A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.62 g of water at 52.3 oC in an insulated container. clear = 0.128

alisha [4.7K]

Answer: The final temperature of both the weight and the water at thermal equilibrium is $50.26^{o}C$ .

Explanation:

The given data is as follows.

mass = 7.62 g, $T_{2} = 10.8^{o}C$

Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.

q = $mC \times \Delta T$

= $7.62 g \times 4.184 J/^{o}C \times (52.3 - T)$

Now, heat gained by lead will be calculated as follows.

q = $mC \times \text{Temperature change of lead}$

= $2.04 \times 0.128 \times (T - 11.0)$

According to the given situation,

Heat lost = Heat gained

$7.62 g \times 4.184 J/^{o}C \times (52.3 - T)$ = $2.04 \times 0.128 \times (T - 11.0)$

T = $50.26^{o}C$

Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is $50.26^{o}C$ .

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ziro4ka [17]

Answer: sorry I’m late but it is 11 electrons

Explanation:

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quester [9]

Answer:

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All i know is that #7 is true

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Answer:

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Explanation:

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