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Gemiola [76]
3 years ago
8

What rule is observed when naming an oxyacid that does have oxygen in its formula?

Chemistry
2 answers:
lesya692 [45]3 years ago
5 0

Answer:

An oxyacid with two less oxygen atoms than the (root)ic acid is named by writing hypo-, then the root of the name for the element other than hydrogen and oxygen, then -ous, and then acid. Therefore, HClO, is hypochlorous acid

Explanation:

Harman [31]3 years ago
4 0

Answer:

Anion name and Acid name

Formula Anion Anion name Acid Name

HF F- is fluoride hydrofluoric acid

HCl Cl- is chloride hydrochloric acid

HBr Br- is bromide hydrobromic acid

HI I

- is iodide hydroiodic acid

H2S S2- is sulfide hydrosulfic acid

HNO2 NO2 is nitrite nitrous acid

HNO3 NO3

-

is nitrate nitric acid

HC2H3O2 C2H3O2

-

is acetate acetic acid

H2SO4 SO4

2- is sulfate sulfuric acid

H2CO3 CO3

2- is carbonate carbonic acid

H3PO4 PO4

3- is phosphate phosphoric acid

HClO ClO¯ is hypoclorite hypochlorous acid

HClO2 ClO2¯ is chlorite chlorous acid

HClO3 ClO3¯ is chlorate chloric acid

HClO4 ClO4¯ is perchlorate perchloric acid

HIO3 IO3¯ is iodate iodic acid

HNO2 NO2¯ is nitrite nitrous acid

H2SO3 SO3

2- is sulfite sulforous acid

HCN CN is cyanide hydrocyanic acid

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At 25 °c, only 0.0100 mol of the generic salt ab2 is soluble in 1.00 l of water. what is the ksp of the salt at 25 °c? ab2(s)↽−−
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A concentrated aqueous solution of Pb(NO3)2 is slowly added to 1.0 L of a mixed aqueous solution containing 0.010 M Na2CrO4 and
Oduvanchick [21]

Answer:

This means the amount of PbCrO4 will precipitate first, with a [Pb^2+] concentration of 1.8*10^-12 M

Explanation:

Step 1: Data given

Molarity of Na2CrO4 = 0.010 M

Molarity of NaBr = 2.5 M

Ksp(PbCrO4) = 1.8 * 10^–14

Ksp(PbBr2) = 6.3 * 10^–6

Step 2: The balanced equation

PbCrO4 →Pb^2+ + CrO4^2-

PbBr2  → Pb^2+ + 2Br-

Step 3: Define Ksp

Ksp PbCrO4 = [Pb^2+]*[CrO4^2-]

1.8*10^-14 = [Pb^2+] * 0.010 M

[Pb^2+] = 1.8*10^-14 /0.010

[Pb^2+] = 1.8*10^-12 M

The minimum [Pb^2+] needed to precipitate PbCrO4 is 1.8*10^-12 M

Ksp PbBr2 = [Pb^2+][Br-]²

6.3 * 10^–6 = [Pb^2+] (2.5)²

[Pb^2+] = 1*10^-6 M

The minimum [Pb^2+] needed to precipitate PbBr2 is 1*10^-6 M

This means the amount of PbCrO4 will precipitate first, with a [Pb^2+] concentration of 1.8*10^-12 M

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3 years ago
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