Question

PLEASE HELP!!!! WILL MARK BRAINLIEST!!!! A rigid steel container with a volume of 30 L is filled with oxygen to a pressure of 9.00 atm at 28.0 °C. What is the pressure in the container if the temperature is raised to 129.0 °C?

Answer 1

Answer:

12 atm

Explanation:

First, let us convert Celcius into Kelvin: 28.0 °C = 301.15 K and 129.0 °C = 402.15 K

For this question we must employ the Combined Gas Law: $\frac{P_1V_1}{P_2V_2}=\frac{n_1RT_1}{n_2RT_2}$, where $P_1$ is the initial pressure and $P_2$ is the new pressure.

We know that intitially, P=9 atm, V=30 L, and T=301.15K. From our problem, only temperature and pressure changes, while the number of moles, volume and the gas constant, R, stay the same, so they are irrelevant.

Thus, the filled out Combined Gas Law would be:

$\frac{9 atm}{P_2}$=$\frac{301.15K}{402.15K}$, where the volume, moles of gas, and R are cancelled out.

We can manipulate this equation to derive the new pressure. We find that

9atm≈0.74885$P_2$.  

This means that

$P_2$≈9/0.74885≈12 atm