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horsena [70]
3 years ago
5

What will happen if you add more dilute to a saturated solution

Chemistry
1 answer:
natita [175]3 years ago
3 0
If you dilute a concentrated solution, the concentration of the obtained solution is smaller than that of the initial solution. But if you add more solute to a concentrated solution, the concentration of the obtained solution is greater than that of the initial.
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The row or period on the periodic table tells us
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Answer:

its a

Explanation:

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Describe a consequence of overpopulation of deer in the forest areas of the northeastern United States
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If the deer population were to overpopulate then that would mean that there would not be enough room for other living things. Also, there would be less grass and plants because of the deer eating it all. Hope this helps!!!
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The density of an object is determined to be 0.6 g/cm3. What is the mass of the object if it takes up 3 cm3 of space?
nikklg [1K]

Answer:

<h2>1.8 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question

volume = 3 cm³

density = 0.6 g/cm³

We have

mass = 0.6 × 3 = 1.8

We have the final answer as

<h3>1.8 g</h3>

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3 years ago
The molar heat capacity of a compound with the formula C2H6SO is 88.0 J/mol-K. The specific heat of this substance is __________
lisabon 2012 [21]

Answer : The specific heat of this substance is, 1.13 J/g.K

Explanation :

Molar heat capacity : It is defined as the amount of heat absorbed by one mole of a substance to raise its temperature by one degree Celsius.

As we are given that the chemical formula of compound is, C_2H_6SO

First we have to calculate the molar mass of given compound.

Molar mass of C_2H_6SO = 2(12g/mol)+6(1g/mol)+32g/mol+16g/mol

Molar mass of C_2H_6SO = 78 g/mol

Now we have to calculate the specific heat of this substance.

Specific heat of this substance = \frac{\text{Molar heat capacity of a compound}}{\text{Molar mass of }C_2H_6SO}

Specific heat of this substance = \frac{88.0J/mol.K}{78g/mol}

Specific heat of this substance = 1.13 J/g.K

Thus, the specific heat of this substance is, 1.13 J/g.K

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Does anyone know how to mark brainliest?
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Just click on that section ( MARK AS BRAINLIEST ) and you'll receive 3 points .

SO PLEASE MARK ME BRAINLIEST !

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