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kotegsom [21]
3 years ago
14

Can someone help me solve this problem?

Mathematics
1 answer:
ioda3 years ago
6 0
The scale factor was D. 4. We can figure this out by multiplying 3 by 4 to get 12 and 1 by 4 which is 4 to get the dimensions of the larger triangle.
I hope this helped! :-)
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ASAP!! Three consecutive numbers have a sum of 156. What are the 3 numbers?
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For this problem, all you need to do is find the three #'s that add up to 156.

So, lets look at the answers and add them up.

A. 50, 52, 54

50 + 52 + 54 = 156

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51 + 52 + 53 = 156

C. 49,50,51

49 + 50 + 51 = 150

D. 49,51,53

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Read 2 more answers
Given triangle PRS is congruent to triangle CFH, find the values of x, y, and z.
Mashutka [201]

Answer:

x = 23

y = 7

z = 11

Step-by-step explanation:

Since ∆PRS ≅ ∆CFH, therefore,

m<R = m<F

13y - 1 = 90° (substitution)

Add 1 to both sides

13y - 1 + 1 = 90 + 1

13y = 91

Divide both sides by 13

13y/13 = 91/13

y = 7

Since ∆PRS ≅ ∆CFH, therefore,

PS = CH

2x - 7 = 39 (substitution)

Add 7 to both sides

2x - 7 + 7 = 39 + 7

2x = 46

Divide both sides by 2

2x/2 = 46/2

x = 23

Since ∆PRS ≅ ∆CFH, therefore,

m<S = m<H

Find m<S

m<S = 180 - (m<P + m<R) (sum of ∆)

m<S = 180 - (28 + (13y - 1)) (substitution)

Plug in the value of y

m<S = 180 - (28 + (13)(7) - 1))

m<S = 180 - (28 + 91 - 1)

m<S = 180 - 118

m<S = 62°

Therefore, since m<S = m<H,

62° = 6z - 4 (substitution)

Add 4 to both sides

62 + 4 = 6z - 4 + 4

66 = 6z

Divide both sides by 6

66/6 = 6z/6

11 = z

7 0
3 years ago
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