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2 years ago

5) Is 3 a zero (or root) of f(x) = x3 - 9x2 + 11x + 21?

Mathematics

1 answer:

frozen [14]2 years ago

6 0

Answer:

Yes

Step-by-step explanation:

f(x) = x³ − 9x² + 11x + 21

f(3) = (3)³ − 9(3)² + 11(3) + 21

f(3) = 27 − 81 + 33 + 21

f(3) = 0

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What is 832 times 1 equal to?

denpristay [2]

Answer:

832

Step-by-step explanation:

If you have one group of 832, and put it into 1 group you get 832

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1 year ago

41) Gabriella invests $8,193 in a retirement

nataly862011 [7]

Answer:

Option C. $\$34,252.67$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=18\ years\\ P=\$8,193\\ r=0.08\\n=6$

substitute in the formula above

$A=\$8,193(1+\frac{0.08}{6})^{6*18}=\$34,252.67$

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2 years ago

Which of the following is a sensory organ?

Ksenya-84 [330]

Answer:

Eyes

Step-by-step explanation:

I’m pretty sure

3 0

2 years ago

Read 2 more answers

Find the volume of the region bounded above by the elliptical paraboloid zequals=9 minus 4 x squared minus 5 y squared9−4x2−5y2

Virty [35]

Answer:

$\int\limits^1_0 \int^1_0{z} \, dA$

Step-by-step explanation:

$\int\limits^1_0\int^1_0 {9-4x^2-5y^2dy} \, dx$

$\int\limits^1_0 {9y-4x^2y-\frac{5y^3}{3}|_0 ^1 } \, dx$

$\int\limits^1_0 {22/3 -4x^2} \, dx$

You finish the leftover.

7 0

2 years ago

Use a matrix equation to solve the system of linear equations. left brace Start 2 By 1 Matrix 1st Row 1st Column 2nd Row 1st Col

natali 33 [55]

Answer:

$\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]$

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

$\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]$

To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.

$A^{-1}$ = (1 / determinant of A) x Adjoint of A

the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2

Adjoint of A = $\left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]$

$A^{-1}$ = $\frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right]$ = $\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]$

4 0

2 years ago