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3 years ago

Solve for x round to the nearest tenth of a degree,if necessary.

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

4 0

Answer:

Solution given:

Cos X=Adjacent/hypotenuse

Cos X=6.5/8.4

x=Cos-¹(6.5/8.4)

x=39.3°

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Irina18 [472]

The answer for #1 and 2
1)B 5.007x10 -3
2)B 103,150

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3 years ago

1+Sin/Cos + Cos/1+Sin = 2Sec

Bond [772]

Step-by-step explanation:

Consider the left-hand side:

$\dfrac{1+\sin{\theta}}{\cos{\theta}} + \dfrac{\cos{\theta}}{1+\sin{\theta}}$

$\:\:\:\:= \dfrac{(1+\sin{\theta})^2 + \cos^2{\theta}}{\cos{\theta}(1+\sin{\theta})}$

$\:\:\:\:=\dfrac{1+2\sin{\theta}+\sin^2{\theta} + \cos^2{\theta}}{\cos{\theta}(1+\sin{\theta})}$

$\:\:\:\:=\dfrac{2+2\sin{\theta}}{\cos{\theta}(1+\sin{\theta})} =\dfrac{2(1+\sin{\theta})}{\cos{\theta}(1+\sin{\theta})}$

$\:\:\:\:= \dfrac{2}{\cos{\theta}} = 2\sec{\theta}$

7 0

3 years ago

5/8 of the cats perferred drinking with there tongue but 3/16 wanted a straw if there was 39 cats that gave one of these 2 answe

AveGali [126]

Answer:

208cats

Step-by-step explanation:

⅝=tongue

³/16=straw=39cats

⅝+³/16=13/16

meaning total number of cats is 16/16

If ³/16=39cats

16/16=?

39×16/3

=208cats

6 0

3 years ago

2) The results of a 2012 Pew Foundation survey of high school and middle school teachers is given in the pie chart. A student as

Serggg [28]

Answer:

The calculated value z = 9.4451 > 1.96 at 5% level of significance.

Null hypothesis is rejected at 5% level of significance

yes there is difference in the distribution of types of cell phones for the teachers in 2018 at a 5% level of significance

Step-by-step explanation:

Explanation:-

Step:- (1)

The results of a 2012 Pew Foundation survey of high school and middle school teachers is given in the pie chart.

A student asked a random sample of teachers in 2018 and found 165 had smart-phones, 80 had a cell phone

The first sample proportion

$p_{1} = \frac{80}{165} = 0.4848$

A student asked a random sample of teachers in 2018 and found 165 had smart-phones,5 had no cell phone

The second sample proportion

$p_{2} = \frac{5}{165} = 0.03030$

Step :-(ii)

Null hypothesis :H₀: Assume that there is no difference in the distribution of types of cell phones for the teachers in 2018

H₀ : p₁ = p₂

Alternative hypothesis :H₁

H₁ : p₁ ≠ p₂

Level of significance : ∝=0.05

The tabulated value z=1.96

Step:-(iii)

The test statistic

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} } } +\frac{1}{n_{2} } )} }$

where $p = \frac{n_{1}p_{1} +n_{2} p_{2} }{n_{1} + n_{2} }$

q = 1-p

In given data n₁ = n₂ = n

$p = \frac{165 (0.4848)+165 (0.03030 }{165 + 165}$

on calculation , we get p = 0.2655

q =1-p = 1-0.2655

q = 0.7345

$Z = \frac{0.4848 -0.030}{\sqrt{0.2655X0.7345(\frac{1}{165 } } +\frac{1}{165} )} }$

Z = 9.4451

The calculated value z = 9.4451 > 1.96 at 5% level of significance.

Conclusion:-

Null hypothesis is rejected at 5% level of significance

yes there is difference in the distribution of types of cell phones for the teachers in 2018 at a 5% level of significance

6 0

4 years ago

Solve pls brainliest

Pavel [41]

Answer:

-3

Step-by-step explanation:

using pemdas, we first divide -18 by 6 to get -3. next, we subtract -3 from -6: -6-(-3)=-6+3=-3

3 0

3 years ago

Read 2 more answers

Solve for x round to the nearest tenth of a degree,if necessary.​

Solve for x round to the nearest tenth of a degree,if necessary.