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Zolol [24]
3 years ago
6

I need help pls. Question 11

Mathematics
1 answer:
g100num [7]3 years ago
3 0

Answer:

T = .17m + 50

Step-by-step explanation:

T = Total cost

M = Mile

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2 / 14 , 3/21 , 4/28

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51 . 4965 X _______ = 5149 . 65<br> Pls fasr
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<em>51 . 4965 X </em><em><u>1</u></em><em><u>0</u></em><em><u>0</u></em><em>= 5149 . 65</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>correct</em><em> </em><em>answer</em><em>.</em>

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A test takes less than 50 minutes to complete. Thirty-eight minutes have passed. Which inequality represents m, the possible num
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Step-by-step explanation:

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Which arrangement shows275, 5.36, 535, and 336 in order from least to greatest?
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3 years ago
Please help find them <br>1 AB<br><br>2 BC​
spin [16.1K]

Answer:

AB ≈ 15.7 cm, BC ≈ 18.7 cm

Step-by-step explanation:

(1)

Using the Cosine rule in Δ ABD

AB² = 12.4² + 16.5² - (2 × 12.4 × 16.5 × cos64° )

       = 153.76 + 272.25 - (409.2 cos64° )

       = 426.01 - 179.38

       = 246.63 ( take the square root of both sides )

AB = \sqrt{246.63} ≈ 15.7 cm ( to 1 dec. place )

(2)

Calculate ∠ BCD in Δ BCD

∠ BCD = 180° - (53 +  95)° ← angle sum in triangle

∠ BCD = 180° - 148° = 32°

Using the Sine rule in Δ BCD

\frac{BC}{sin53} = \frac{BD}{sin32} = \frac{12.4}{sin32} ( cross- multiply )

BC × sin32° = 12.4 × sin53° ( divide both sides by sin32° )

BC = \frac{12.4sin53}{sin32} ≈ 18.7 cm ( to 1 dec. place )

         

6 0
2 years ago
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