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-BARSIC- [3]
3 years ago
14

An equation that is true for every value of the variables is a(n)

Mathematics
2 answers:
svetlana [45]3 years ago
7 0
I pretty sure its called a <span>called an [b] identity [/b]. i remember learning this and i am almost certain that this is what it's called

</span>
Roman55 [17]3 years ago
5 0
Identity, <span>For example, x + x = 2x is </span>true for every value<span> of x.</span>
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If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=
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now, if we just knew what g(2)  is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that  means if we use that value in f(x),   f( some range value) = 2

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thus    2 = 2x+sin(x)

\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2&#10;\\\\\\&#10;-----------------------------\\\\&#10;g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it
5 0
3 years ago
The monthly average temperature, T, for San Francisco is usually within 7.5 degrees and 56.5 degrees, inclusive. What is the mon
erica [24]
49 es la temperatura mensual
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3 years ago
If f(x)= 3/x+2- square root x-3, complete the following statement: f(19)=
I am Lyosha [343]

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round

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The domain of the function is the set of all the values of x that would allow the function to have real values. Since the radicand is x - 3, the value of x cannot be less than 3 because that would make the value of sqrt (x - 3) an imaginary number. Thus, the domain should be all numbers GREATER than or equal to 3.

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3 years ago
Please help me with this
oksano4ka [1.4K]

Answer:

m∠1=80°, m∠2=35°, m∠3=33°

Step-by-step explanation:

we know that

The sum of the interior angles of a triangle must be equal to 180 degrees

step 1

Find the measure of angle 1

In the triangle that contain the interior angle 1

∠1+69°+31°=180°

∠1+100°=180°

∠1=180°-100°=80°

step 2

Find the measure of angle 2

In the small triangle that contain the interior angle 2

∠2+45°+(180°-∠1)=180°

substitute the value of angle 1

∠2+45°+(180°-80°)=180°

∠2+45°+(100°)=180°

∠2+145°=180°

∠2=180°-145°=35°

step 3

Find the measure of angle 3

In the larger triangle that contain the interior angle 3

(∠3+31°)+69°+47°=180°

∠3+147°=180°

∠3=180°-147°=33°

3 0
3 years ago
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