Answer:
2(4x-6)
4(2x-3)
8(x-3/2)
Step-by-step explanation:
find all factors of 8 other than 1, you should have 3
divide the whole equation by the factor then multiply by the factor
2(8x-12)/2 = 2(4x-6)
4(2x-3)
8(x-3/2)
The square of a binomial is written like
In your case, you have 
, which implies 
So, we want to write
But our left hand side is
If we add 26 to both sides, we have
an = a1r^(n-1)
a5 = a1 r^(5-1)
-6 =a1 r^4
a2 = a1 r^(2-1)
-48 = a1 r
divide
-6 =a1 r^4
---------------- yields 1/8 = r^3 take the cube root or each side
-48 = a1 r 1/2 = r
an = a1r^(n-1)
an = a1 (1/2)^ (n-1)
-48 = a1 (1/2) ^1
divide by 1/2
-96 = a1
an = -96 (1/2)^ (n-1)
the sum
Sn = a1[(r^n - 1/(r - 1)]
S18 = -96 [( (1/2) ^17 -1/ (1/2 -1)]
=-96 [ (1/2) ^ 17 -1 /-1/2]
= 192 * [-131071/131072]
approximately -192
(2)5x-y=12
3x+2y=2
10x-2y=12
3x+2y=2
13x=2
x=0.15
