The circle below is centered at the point (3,1) and has a radius length of 2.What is its equation

Mathematics

1 answer:

hammer [34]3 years ago

7 0

Answer:

C. $(x-3)^2+(y-1)^2=2^2$

Step-by-step explanation:

The standard equation of a circle, given the radius r units and center (h,k) is given by:

$(x-h)^2+(y-k)^2=r^2$

From the question, we have the center of the circle to be (3,1) and the radius is 2 units.

We substitute the center and radius of the circle into the equation to get:

$(x-3)^2+(y-1)^2=2^2$

The correct answer is C

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Use 3.1 < sqrt 10 <3.2 to find the possible values of each expression. 2+sqrt 10

lilavasa [31]

The inequality which represents possible values of the expression 2+sqrt 10 by virtue of the given inequality; 3.1 < sqrt 10 < 3.2 as in the task content is; 5.1 < 2 + sqrt 10 < 5.2.

<h3>Which inequality correctly expresses the possible values of the expression; 2 + √10 as required in the task content?</h3>

It follows from the task content that the expression given is;

3.1 < sqrt 10 < 3.2

Since the given premises is an inequality, it follows that adding the same number to all parts of the inequality stills holds the inequality true.

Hence by adding 2 to all parts of the inequality, we have;

2 + 3.1 < 2 + sqrt 10 < 2 + 3.2

Therefore, we have;

5.1 < 2 + sqrt 10 < 5.2

Ultimately, 5.1 < 2 + sqrt 10 < 5.2 represent the possible values of the expression 2+sqrt 10 as given by the inequality 3.1 < sqrt 10 < 3.2.