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Olegator [25]
3 years ago
7

The circle below is centered at the point (3,1) and has a radius length of 2.What is its equation

Mathematics
1 answer:
hammer [34]3 years ago
7 0

Answer:

C. (x-3)^2+(y-1)^2=2^2

Step-by-step explanation:

The standard equation of a circle, given the radius r units and center (h,k) is given by:

(x-h)^2+(y-k)^2=r^2

From the question, we have the center of the circle to be (3,1) and the radius is 2 units.

We substitute the center and radius of the circle into the equation to get:

(x-3)^2+(y-1)^2=2^2

The correct answer is C

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