Answer:
x/2 + y/3 = 1
Step-by-step explanation:
using this formula
x/a + y/b = 1 , where a and b are the coordinates of x and y axes respectively.
Perpendicular slopes have a product of -1, thus

solve for "d"
First you must find X by setting the sides equal to each other. from that you know x=4 then plug that into the w/ they give you the Equation to. = 6then multiply by 2 and you get 12
Answer:
Domain : (-∞,∞) Range : (-∞,∞)
Step-by-step explanation:
Given:
f(x) = 3x+5
To find: Domain and Range of f(x)
Domain is the set of values that x can take.
Range is the set of values of y corresponding to the values of x in the domain.
Here x can take any value and the domain is the set of real numbers i.e (-∞,∞).
f(x) = 3x + 5
The graph of f(x) is a straight line that extends from -∞ to +∞ and hence the range is (-∞,∞).
W=mg
<span>Where: </span>
<span>Weight = mass * acceleration due to gravity </span>
<span>So let's say I want to work out my weight on the moon. I know I weigh about 70kg (which would be N), but I can't use that figure for the calculation on the moon. That is what I weigh on Earth, so let's look at the equation... </span>
<span>70kg = mass * 9.81m/s^2 </span>
<span>Where 9.81m/s^2 is the acceleration due to gravity on the surface on the earth. I want to get rid of that, so let's work out my mass by division; </span>
<span>70/9.81 = 7.14kg </span>
<span>I googled the acceleration of gravity on the Moon, which was = 1.6m/s^2 </span>
<span>Let's use that in the same equation W=mg </span>
<span>W = 7.14kg * 1.6m/s^2 = 11.42N
</span><span>On the Moon, you would weigh approximately one sixth of your weight on Earth, so if your bathroom scales tell you you weigh 120 pounds, there you would weigh 20 pounds.
</span>
<span>Moon`s gravitational pull is about one-sixth to the gravitational pull on earth hence weight on moon is about one-sixth of the weight on earth.</span>