All categories

3 years ago

Factor-

Mathematics

1 answer:

Nastasia [14]3 years ago

4 0

Hello from MrBillDoesMath!

Answer:

See Discussion section below

Discussion:

2x^2 + 5x + 3 = (2x+3)(x+1) which is Choice 3

3x^2+10x+4 =-1/3 (-3 x + sqrt(13) - 5) (3 x + sqrt(13) + 5)

I don't think any of the provided choices are right!

8x^2+10x-3 = (2x+3)(4x-1) which is Choice 2

6x^2-7x-4 = -1/24 (-12 x + sqrt(145) + 7) (12 x + sqrt(145) - 7)

I don't think any of the provided choices are right!

2x^2+x-28 = (2x-7)(x+4) which is Choice 2

Thank you,

MrB

You might be interested in

−6(x+7)=−4x−2 how many solutions

yaroslaw [1]

Answer: There is one solution, -20

Step-by-step explanation:

$-6(x+7)=-4x-2\\\\Distribute\\\\-6x-42=-4x-2\\\\Add(6x)\\\\-42=2x-2\\\\Add(2)\\\\-40=2x\\\\x=-20$

There is one solution, -20

Hope it helps <3

8 0

3 years ago

Read 2 more answers

Terrence took a total of 16 pages of notes during 8 hours of class. In all, how many hours will

r-ruslan [8.4K]

16 pages/8 hrs

2 pages/ he

18/2=9

18 pages/9 hrs

9 hours is your answer.

3 0

2 years ago

24 swimmers are swimming in the pool. 9 of them are female. What fraction of swimmers are male?

Korolek [52]

Answer:

15/24 or 5/8

Step-by-step explanation:

Well 9 are female

The rest of the 24 has to be male so

24-9=15

15/24 or 5/8

7 0

3 years ago

Change the equation of the circle x^2+14x+y^2-10y=14x 2 + 14 x + y 2 − 10 y = 14 into center-radius form of a circle.

jonny [76]

Answer:

The answer to your question is (x + 7)² + (y - 5)² = 88

Step-by-step explanation:

Equation

x² + 14x + y² - 10y = 14

Complete perfect trinomial squares

x² + 14x + (7)² + y² - 10y + (5)² = 14 + (7)² + (5)²

Simplify

x² + 14x + (7)² + y² - 10y + (5)² = 14 + 49 + 25

x² + 14x + (7)² + y² - 10y + (5)² = 88

Factor

(x + 7)² + (y - 5)² = 88 This is the equation in the form

center-radius

7 0

3 years ago

If f(x)=x^2- 4 and g(x)=x^2 plus 2 x,

gregori [183]

Answer:

$\huge\boxed{(f-g)\left(-\dfrac{1}{3}\right)=-3\dfrac{1}{3}}$

Step-by-step explanation:

$\text{We have}:\\\\f(x)=x^2-4\ \text{and}\ g(x)=x^2+2x\\\\(f-g)(x)=f(x)-g(x)\\\\\text{therefore}\\\\(f-g)(x)=(x^2-4)-(x^2+2x)=x^2-4-x^2-2x\\\\=(x^2-x^2)-2x-4=-2x-4\\\\(f-g)\left(-\dfrac{1}{3}\right)\to\text{put}\ x=-\dfrac{1}{3}\ \text{to the equation of the function}\ (f-g)(x):\\\\(f-g)\left(-\dfrac{1}{3}\right)=-2\left(-\dfrac{1}{3}\right)-4=\dfrac{2}{3}-4=-3\dfrac{1}{3}$

6 0

3 years ago