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dimaraw [331]
3 years ago
13

Decide which story can be represented by the system of equations below.

Mathematics
2 answers:
serg [7]3 years ago
6 0
This looks very confusing how do you deal with this
MatroZZZ [7]3 years ago
4 0

Answer:

Step-by-step explanation:

am i dum or is this super confusing

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Need help on #5, please help :)
Gre4nikov [31]
Okay i answered by comment but now i can make an official answer here:

a) i got 5,828.6 grams / about 13lb

b) i got 273,391.48$

hope this helps!
6 0
3 years ago
What is the domain of the following graph?
Morgarella [4.7K]

Answer:

[0,9]

Step-by-step explanation:

The domain is the first set of the ordered pair. When finding the domain you are supposed to find which x value it starts from to where it ends. The x value starts from 0 and ends and the 9th unit on the x-axis which would give us 0,9 now since both points are closed you would use these symbols [ ] to show that it is closed meaning the answer would be [0,9]

Note:

I'm sorry if this is wrong but this is what I believe the answer is.

4 0
3 years ago
A) 75YARDS B) 85 YARDS C)80 YARDS D) 90 YARDS
Amanda [17]

Answer:

________________

I think it's 85 yards

7 0
3 years ago
Help can't figure this problem out
Darya [45]
(x^1/2 y^-2/3)^-6
= x^(1/2*-6) y^[(-2/3) *(-6)]
= x^-3 y ^4
= y^4 / x^3

answer is D.  y^4 / x^3  
8 0
3 years ago
Assuming the conditions regarding the motion represented in the graph remain the same, determine the acceleration of the object
vovikov84 [41]

(a)

We can see that

this is a straight line

and this is the graph of velocity

we know that

acceleration is the derivative of velocity

so, slope of curve of velocity is acceleration

so, we will find slope of this line

We can select any two points

(0,4) and (5,7)

we can use slope formula

m=\frac{y_2-y_1}{x_2-x_1}

now, we can plug points

m=\frac{7-4}{5-0}

m=0.6

we know that slope of line is always constant irrespective of any value of t

so, acceleration will always be same irrespective of any value of t

so, we will get acceleration

a(t)=0.6m/s^2............Answer

(b)

we can see that acceleration is constant

and we know that

derivative of constant is always 0

so, instantaneous rate of acceleration at t=10s is 0........Answer

7 0
3 years ago
Read 2 more answers
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