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3 years ago

Decide which story can be represented by the system of equations below.

Mathematics

2 answers:

serg [7]3 years ago

6 0

This looks very confusing how do you deal with this

MatroZZZ [7]3 years ago

4 0

Answer:

Step-by-step explanation:

am i dum or is this super confusing

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A Cepheid variable star is a star whose brightness alternately increases and decreases. Suppose that Cephei Joe is a star for wh

4vir4ik [10]

Answer:

$\dfrac{0.7\pi}{5.3}\cos(\dfrac{2\pi t}{5.3})$

0.16

Step-by-step explanation:

According to the question the mathematical model should be

$B(t)=2.9+0.35\sin(\dfrac{2\pi t}{5.3})$

Differentiating with respect to time we get

$B'(t)=0.35\cos(\dfrac{2\pi t}{5.3})\times(\dfrac{2\pi}{5.3})\\\Rightarrow B'(t)=\dfrac{0.7\pi}{5.3}\cos(\dfrac{2\pi t}{5.3})$

So, the rate of change of brightness after t days is $\dfrac{0.7\pi}{5.3}\cos(\dfrac{2\pi t}{5.3})$

After 1 day means $t=1$

$B'(1)=\dfrac{0.7\pi}{5.3}\cos(\dfrac{2\pi\times 1}{5.3})\\\Rightarrow B'(1)=0.16$

The rate of increase after one day is 0.16.

8 0

3 years ago

Help me plz!!!******

kupik [55]

The first answer is correct

7 0

3 years ago

Determine the equations of the vertical and horizontal asymptotes if any for h(x)=(x+1)^2/x^2-1

shepuryov [24]

ANSWER

Vertical asymptote:

x=1

Horizontal asymptote:

y=1

EXPLANATION

The given rational function is

$h(x) = \frac{ {(x + 1)}^{2} }{ {x}^{2} - 1 }$

$h(x) = \frac{ {(x + 1)}^{2} }{ ({x} - 1)(x + 1)}$

$h(x) = \frac{ (x + 1)(x + 1) }{ ({x} - 1)(x + 1)}$

$h(x) = \frac{ x + 1}{ {x} - 1}$

The vertical asymptote occurs at

${x} - 1 = 0$

$x = 1$

The vertical asymptotes is x=1

The degree of the numerator is the same as the degree of the denominator.

The horizontal asymptote of such rational function is found by expressing the coefficient of the leading term in the numerator over that of the denominator.

$y = \frac{1}{1}$

y=1

8 0

3 years ago

Find the values of x and y. Leave answers in simplest radical form.<br>

NNADVOKAT [17]

$\sin(60°) = \frac{x}{14} \Leftrightarrow x = 14 \sin(60°) = \frac{14 \sqrt{3} }{2} = 7 \sqrt{3} \\ \cos(60°) = \frac{y}{14} \Leftrightarrow y = 14\cos(60°) = \frac{14}{2} = 7$