Answer:
<em>The answer is 1.2001 * 10^-5</em>
Answer:
If all you care about is whether you roll 2 or not, you get a Binomial distribution with an individual success probability 1/6. The probability of rolling 2 at least two times, is the same as the probability of not rolling 2 at zero or one time.
the answer is, 1 - bin(k=0, n=4, r=1/6) - bin(k=1, n=4, r=1/6). This evaluates to about 13%, just like your result (you just computed all three outcomes satisfying the proposition rather than the two that didn’t).
Step-by-step explanation:
<span>In order to determine the total number of errors that were made by the bar code scanner, we first have to calculate how many total scans were made. Because there were six items scanned 1,000 times each, there were 6,000 total scans made. Next, we have to add up the total number of errors made by each item (36+14+21+39+11+2). As a result, there were a total of 123 errors made during the 6,000 scans.</span>
Answer:
The answer is D)-2x-11y-13
Step-by-step explanation:
