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yKpoI14uk [10]
3 years ago
10

The small rectangle was enlarged to create the big rectangle. A smaller rectangle has a length of 12 feet and a width of 2 feet.

A larger rectangle has a length of x feet and a width of 5 feet. Not drawn to scale What is the missing measure on the big rectangle?
Mathematics
2 answers:
Anarel [89]3 years ago
8 0

Answer:

the bigger rectangle = 30 x 5

Step-by-step explanation:

divide the bigger width by the smaller width to find the rate of change (2.5) and multiply both numbers (length and width) to get the larger rectangle.

zhuklara [117]3 years ago
6 0

Answer:

30

Step-by-step explanation:

30

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Answer:

see explanation

Step-by-step explanation:

To show f and g are inverses we require to show that

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4 years ago
(a) Show that a differentiable function f decreases most rapidly at x in the direction opposite the gradient vector, that is, in
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Answer:

Step-by-step explanation:

\text{Show that a differentiable function f decreases most rapidly at x in the }

\text{direction opposite the gradient vector, that is, in the direction of} -\bigtriangledown f(x)\text{. Let}\  \theta \ \text{be the angle between} \bigtriangledown f(x) \  \text{and unit vector u. Then } D_u f = \mathbf{|\bigtriangledown f| \  cos  \ \theta }}

\text{Since the minimum value of} \ \  \mathbf{cos   \ \theta} \  \ is \mathbf{-1} \  \text{occuring \ for \ 0} \le \ \theta \ < 2x,  \\ \\ when  \ \theta = \mathbf{\pi} , \text{the mnimum value of} \  D_uf  \ is} -|\bigtriangledown f|,  \text{occuring when the direction of u is } \\ \\  \ \mathbf{the \ opposite \  of} \  \text{the direction of }  \ \bigtriangledown f (assuming \ \bigtriangledown f\ is \  not \ zero)

b) \text{From part A:}

If \ f(x,y) = x^4y -x^2y^2 \ \  decreases \ fastest \ at \ the \point \ (2,-5)\\ \\ F(x,y) = x^4y -x^2y^3 \\ \\ f_x = \dfrac{df}{dx}= \dfrac{d}{dx}(x^4y-x^2y^3)  \\ \\ f_x = \dfrac{df}{dx}= y4x^3 -2y^3x  \\ \\ For(2,-5) \\ \\ f_x = (-5)4(2)^3 -2(-5)^3(2) \\ \\ \mathbf{ f_x = 340}

However; f_y = \dfrac{df}{dy} = \dfrac{d}{dy}(x^4y - x^2y^3) \\ \\ f_y = x^4 -3x^2y^2 \\ \\  Now, for (2, -5)\\ \\f_y = (2)^4 -3(2)^2(-5)^2 \\ \\ f_y = -284

So; \bigtriangledown = < 340,-284> \text{this is the direction of fastest decrease}

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hmm so....  notice the picture you have there, is just an "isosceles trapezoid", namely, it has two equal sides, the left and right one, namely JL and KM

the midpoint of JL is H and the midpoint of KM is N

thus

\bf \textit{middle point of 2 points }\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ \square}}\quad ,&{{ \square}})\quad &#10;%  (c,d)&#10;&({{ \square}}\quad ,&{{ \square}})&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\\\\&#10;-----------------------------\\\\

\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;J&({{ 4m}}\quad ,&{{ 4n}})\quad &#10;%  (c,d)&#10;L&({{ 0}}\quad ,&{{ 0}})&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{0+4m}{2}\quad ,\quad \cfrac{0+4n}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{4m}{2},\cfrac{4n}{2} \right)\implies \boxed{(2m,2n)\impliedby H}\\\\&#10;-----------------------------\\\\

\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;K&({{ 4q}}\quad ,&{{ 4n}})\quad &#10;%  (c,d)&#10;M&({{ 4p}}\quad ,&{{ 0}})&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{4p+4q}{2}\quad ,\quad \cfrac{0+4n}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{2(2p+2q)}{2},\cfrac{4n}{2} \right)\implies \boxed{[(2p+2q), 2n]\impliedby N}\\\\&#10;-----------------------------\\\\

\bf \textit{so, the midpoint of HN is }&#10;\\\\\\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;H&({{ 2m}}\quad ,&{{ 2n}})\quad &#10;%  (c,d)&#10;N&({{ 2p+2q}}\quad ,&{{ 2n}})&#10;\end{array}\\\\\\&#10;%   coordinates of midpoint &#10;\left(\cfrac{(2p+2q)+2m}{2}\quad ,\quad \cfrac{2n+2n}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{2(p+q+m)}{2},\cfrac{4n}{2} \right)\implies (p+q+m)\quad ,\quad 2n
5 0
3 years ago
Read 2 more answers
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