Hello,
Use the factoration
a^2 - b^2 = (a - b)(a + b)
Then,
x^2 - 81 = x^2 - 9^2
x^2 - 9^2 = ( x - 9).(x + 9)
Then,
Lim (x^2- 81) /(x+9)
= Lim (x -9)(x+9)/(x+9)
Simplity x + 9
Lim (x -9)
Now replace x = -9
Lim ( -9 -9)
Lim -18 = -18
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The second method without using factorization would be to calculate the limit by the hospital rule.
Lim f(x)/g(x) = lim f(x)'/g(x)'
Where,
f(x)' and g(x)' are the derivates.
Let f(x) = x^2 -81
f(x)' = 2x + 0
f(x)' = 2x
Let g(x) = x +9
g(x)' = 1 + 0
g(x)' = 1
Then the Lim stay:
Lim (x^2 -81)/(x+9) = Lim 2x /1
Now replace x = -9
Lim 2×-9 = Lim -18
= -18
The answer is most likely (c).
Honestly I don’t remember how to do this but u can try .083 but don’t count on it
The degree of a polynomial is the highest power of the polynomial.
The polynomial is 
The degree is given as:
The zero is given as:
Add 3 to both sides
From the question, we understand that the polynomial has a single zero.
So, the polynomial is:
Substitute 4 for n
Hence, the polynomial is
Read more about polynomials at:
brainly.com/question/11536910
Answer:
-12.706
Step-by-step explanation:
First we distribute: 1 - 12.166 - 1.54
Then we subtract: -12.706
