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navik [9.2K]
3 years ago
5

Solve it (2⋅3) ^2−5 ^2=

Mathematics
2 answers:
lbvjy [14]3 years ago
8 0

Answer:

11

Step-by-step explanation:

(2⋅3) ^2−5 ^2= (6+5)(6-5)=11*1= 11

sattari [20]3 years ago
5 0

Answer:

11

Step-by-step explanation:

(2×3)^2 = 6^2 = 36

5^2 = 25

(2×3)^2 - 5^2 = 36 - 25 = 11

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An isotope of iodine has a mass of 134 amu. How many neutrons does the
Nina [5.8K]

Answer:

The correct option is C: the isotope of iodine contains 81 neutrons.

Step-by-step explanation:

The mass (A) of the iodine isotope is given by:

A = Z + N

Where:

Z: is the number of protons

N: is the number of neutrons

For iodine Z= 53, so if A = 134 the number of neutrons is:

N = A - Z = 134 - 53 = 81

Therefore, the correct option is C. The isotope of iodine contains 81 neutrons.

I hope it helps you!

5 0
3 years ago
N+7/d+7=3/4 solved for d.
spin [16.1K]
D = -28 / 4N+25
Hope this helps. 
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3 years ago
Please help!
Art [367]

Answer:

I believe it is C. The square root of 47

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
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Answer:

7.071 cm

Step-by-step explanation:

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3 years ago
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