Answer:
$8.40
Step-by-step explanation:
12.00 x .30= 3.60
12.00-3.60=8.40
Answer
Find out the percentage of students from the north side of the city in the program .
To prove
Formula
As given
A magnet school program was set up to bring in students from all over the city. With the first 112 students .
the magnet program had 50% from the south side of town, 12.5% from the north side l, and 37.5% from the east side.
12 .5 % is written in the decimal form.
= 0.125
North side student be = 0.125 × 112
= 14
As given
If 6 more student from the north side and 2 students from the west side side enrolled in the program .
than north side student becomes = 14 + 6
= 20
Total number of student becomes = 112 + 6 + 2
= 120
put in the above formula
= 16.66% (approx)
Therefore 16.66% (approx) students from the north side of the city in the program .
Answer:
The probability that a student takes Spanish given that the student is taking Computer Programming = 0.375
Step-by-step explanation:
Given -
Let event A = student takes Spanish
Event B = student takes Computer Programming
= student takes Computer Programming and Spanish
P(B) = 0.4 , = 0.15
What is the probability that a student takes Spanish given that the student is taking Computer Programming =
(Probability of an event occuring given that another event has already occured , we use condition probability )
=
= 0.375
Answer:
YES ALL THE CONDITIONS HAVE BEEN MET
Step-by-step explanation:
H o:mu1=mu2
Ha:mu1 not = mu2
n1=30
n2=30
large samples follows normal distribution
and they are independent samples
we can conduct t test for 2 groups we can ignore that condition randomness
YES ALL THE CONDITIONS HAVE BEEN MET
Answer:
. 2 m/s
Step-by-step explanation:
Speed is defined as the rate of change in distance per time.
in this case you can simply observe the graph to get the final and initial distances & time.
The motion starts from 0 and moves to 2 if you look at the y axis of the graph.
Thus, the initial distance is 0m & the final distance is 2m
The time is specified in the question to have an initial of 0 sec and a final of 1 sec.
now let's plot our values out as a given.
S1 = 0m t1 = 0 sec
S2 = 2m t2 = 1 sec
and so you're going to have to find the change in time and displacement individually to later engage both in your formula which is - ∆V = ∆S / ∆t
∆S = S2 - S1 = 2m - 0m = 2m.
∆t = t2 - t1 = 1 sec - 0 sec = 1 sec.
∆V = ∆S / ∆t = 2m / 1 sec = 2m/sec (2m/s)