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aleksandr82 [10.1K]
3 years ago
13

Un triángulo isósceles mide 4 cm de base y una altura de 8 cm. Calcula el valor de la hipotenusa x.

Mathematics
1 answer:
Rzqust [24]3 years ago
7 0

Answer:


Step-by-step explanation:


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Based on the measures provided in the diagram, determine the measure of AEG
MArishka [77]

Answer:

277°

Step-by-step explanation:

The measure of arc AEG = AB + BE + EF + FG

The central angle is congruent to the arc that subtends it

∠ ECB = 180° - 44° = 136° ( adjacent angles )

∠ECF = ∠ ACB = 44° ( vertical angles ), thus

AEG = 44° + 136° + 44° + 53° = 277°

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3 years ago
Evaluate 2xy when x=-1/4and y=3
Yanka [14]

Answer:

see above

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2 years ago
Write the equation in slope-intercept form.<br> y−1=45(x+5)
aleksandrvk [35]

Answer:

y=45x+226

Step-by-step explanation:

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2 years ago
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Define z_alpha to be a z-score with an area of alpha to the right. For Example: z_0.10 means P(Z &gt; z_0.10) = 0.10. We would a
Reptile [31]

Answer:

a) P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

"=NORM.INV(0.025,0,1)"

And for this case the two values are :z_{crit}= \pm 1.96

b) P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates \alpha/2 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

"=NORM.INV(alpha/2,0,1)"

c) For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got z_{\alpha/2}=1.64

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Part a

P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

"=NORM.INV(0.025,0,1)"

And for this case the two values are :z_{crit}= \pm 1.96

Part b

P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates \alpha/2 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

"=NORM.INV(alpha/2,0,1)"

Part c

For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got z_{\alpha/2}=1.64

6 0
3 years ago
The graph represents function 1, and the equation represents funtion 2:
horsena [70]

Answer:

8

Step-by-step explanation:

we know that

The rate of change of a linear equation is a constant that is the same that the slope

step 1

we have

The equation of the graph (function 1) is equal to

y=4

Is a horizontal line

The slope is equal to zero

so

The rate of change of function 1 is zero

step 2

The equation of the function 2 is

y=8x+12

This is a linear equation in slope intercept form

where

the slope is equal to m=8

so

The rate of change of function 2 is 8

therefore

The rate of change of function 2 is 8 more than the rate of change of function 1

5 0
2 years ago
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