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3 years ago

5

100 POINTS!! Express in simplest radical form

2 answers:

Radda [10]3 years ago

4 0

Answer:

$\large\boxed{3125x\sqrt[5]{x}}$

Step-by-step explanation:

$\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\sqrt[n]{a^n}=a\\\\\sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\a^n\cdot a^m=a^{n+m}\\---------------------\\\\3125x^\frac{6}{5}=3125\sqrt[5]{x^6}=3125\sqrt[5]{x^{5+1}}=3125\sqrt[5]{x^5\cdot x^1}=3125\sqrt[5]{x^5}\cdot\sqrt[5]{x}\\\\=3125x\sqrt[5]{x}$

skad [1K]3 years ago

3 0

Answer:

3125 x 5th root (x)

Step-by-step explanation:

(3125 ) * x^(6/5)

When we have a some thing to a power greater than 1, we can separate it

We can rewrite 6/5 as 5/5 + 1/5

3125 x^(5/5+1/5)

We know a^ b *a^c = a^(b+c)

3125* x^5/5 * x^ 1/5

x^5/5 is x^1 or just x

3125* x * x^ 1/5

3125 x 5th root (x)

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Where would you plot the vertex on the graph of the following absolute value equation? enter your answer as an ordered pair (x,y

makvit [3.9K]

Answer:

The absolute value vertex is (5, 10). Please check that graph is also attached for the absolute equation with vertex (5, 10).

Step-by-step explanation:

Considering the absolute value equation

$y=|x-5|+10$

To find the x coordinate of the vertex, set the inside of the absolute value $x - 5$ equal to zero.

In this case,

$x - 5=0$

$x=5$

Replace the variable x with 5 back into the equation and solve for y.

$y=|(5)-5|+10$

$y=0+10$

$y = 10$

Therefore, the absolute value vertex is (5, 10). Please check that graph is also attached for the absolute equation with vertex (5, 10).

Keywords: absolute value function, vertex

Learn more about absolute value function from brainly.com/question/6507101

#learnwithBrainly

8 0

3 years ago

If a simple harmonic motion is described by x = 3 cos(πt), starting from t = 0 s, what is the first occurrence of a value of t f

poizon [28]

Answer:

The first occurence of t for which x = 0 is t = 0.5.

Step-by-step explanation:

The harmonic motion is described by the following equation.

$x(t) = 3\cos{\pi t}$

What is the first occurrence of a value of t for which x = 0?

This is t when $x(t) = 0$ . So

$x(t) = 3\cos{\pi t}$

$3\cos{\pi t} = 0$

$\cos{\pi t} = \frac{0}{3}$

$\cos{\pi t} = 0$

The inverse of the cosine is the arcosine. So we apply the arcosine function to both sides of the equality.

$\arccos{\cos{\pi t}} = \arccos{0}$

$\pi t = \frac{\pi}{2}$

$t = \frac{\pi}{2 \pi}$

$t = \frac{1}{2}$

$t = 0.5$

The first occurence of t for which x = 0 is t = 0.5.

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3 years ago

Right answer gets brainlist

stiks02 [169]

Answer:

162

Step-by-step explanation:

6*7= 42. 42*2 = 84.

6*3=18. 18*2 = 36

7*3=21. 21*2 = 42.

84+36+42= 162

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3 years ago

What is the measure of JK

kirill [66]

I think it's B because it's a right angle and it's 90 + 25 =125 hope this helps,

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4 years ago

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Salsk061 [2.6K]

Answer:

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