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Luden [163]
3 years ago
9

The drawing shows a person looking at a building on top of which an antenna is mounted. The horizontal distance between the pers

on’s eyes and the building is 83.2 m. In part a the person is looking at the base of the antenna, and his line of sight makes an angle of 33.3 with the horizontal. In part b the person is looking at the top of the antenna, and his line of sight makes an angle of 35.7o with the horizontal. How tall is the antenna?
Mathematics
1 answer:
prohojiy [21]3 years ago
5 0
Consider the triangles formed by the lines of sight in parts a and b. In part a, the distance from the horizontal to the base of the antenna is 82.0*tan31.0º; in part b, the distance from the horizontal to the top is 82.0*tan34.2º. The antenna height is the difference between these 

<span>h = 82.0*tan34.2º - 82.0*tan31.0º = 82.0*(tan34.2º - tan31.0º) = 6.46 m</span>
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lara [203]

Answer:

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Step-by-step explanation:

2 mangoes - $3

1 mango - $?

3 / 2 = 1.5

So:

1 mango = $1.50

Hope this helped!

(Let me know if I got something wrong!)

5 0
3 years ago
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3 years ago
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weeeeeb [17]

Answer:

y = 6

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6 0
3 years ago
Given m||n, find the value of x.<br> 146°
Alexeev081 [22]

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Austin is on his way home in his car. His drive is 30 miles long. He has finished five-sixths of the drive so far. How far has h
drek231 [11]
30 miles is two-thirds of x (where x is the total distance) 


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90/2 = x 


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The total length of his drive is 45 miles</span><span>
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