X= width of the path.
we can suggest this equation:
(20+2x)(28+2x)=1584
we solve this equation:
(20+2x)(28+2x)=1584
560+40x+56x+4x²=1584
4x²+96x-1024=0
4/4x²+96/4x-1024/4=0/4
x²+24x-256=0
We solve this square equation:
x=[-24⁺₋√(576+1024)]/2=(-24⁺₋40)/2
we have two solutions:
x₁=(-24-40)/2=-32 this solution is not valid.
x₂=(-24+40)/2=8
Answer: the width of the path is 8 m.
Answer:
(-4, -3), (4, -1), (8, 0), (12, 1)
Step-by-step explanation:
The x- and corresponding y-values are listed in the table. Put each pair in parentheses, <em>x-value first</em>. (That is an <em>ordered pair</em>.)
(x, y) = (-4, -3) . . . . from the first table entry
(x, y) = (4, -1) . . . . from the second table entry
(x, y) = (8, 0) . . . . from the third table entry
(x, y) = (12, 1) . . . . from the last table entry
Answer:
4 per hour
8/2=4
Step-by-step explanation:
The correct answer is 18 . if you follow pemdas it really helps.
