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3 years ago

Rewrite as a simplistic fraction. _ 0.7=?

Mathematics

1 answer:

Nitella [24]3 years ago

8 0

Answer: 7/10

Step-by-step explanation:

0.7 = 7/10

i think this is what you are asking

if not, I am so sorry :(

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Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.

sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

$\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ · X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ =I.

First, we have to identify the matrix I. As it was said, the matrix is the identiy matrix, which means

I = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

So, $\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ · X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Isolating the X, we have

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]$ - $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

Resolving:

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]$

X· $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ = $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X= $\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ ⁻¹· $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

$\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]$ · $\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]$ = $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a= $\frac{2}{11}$ ; b= $\frac{7}{33}$ ; c= $\frac{-1}{11}$ and d= $\frac{-3}{11}$ . Substituting:

X= $\left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11} \end{array}\right]$ · $\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]$

Multiplying the matrices, we have

X= $\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11} \end{array}\right]$

6 0

3 years ago

Write an equation of the line that passes through the point (-4,-1) and is parallel and perpendicular to the line 2x+7y=14

Darina [25.2K]

Answer: Parallel: y=-2/7x-2 1/7 Perpendicular: y=7/2x+13

Step-by-step explanation:

2x+7y=14

Subtract 2x from both sides.

7y=-2x+14

Divide both sides by 7 to isolate y.

y=-2/7x+2

Parallel:

Plug in x and y with same slope as the original.

-1=-2/7(-4)+b

Solve for b:

-1=8/7+b

-2 1/7=b

y=-2/7x-2 1/7

Perpendicular:

Plug in x and y with the negative inverse of the original slope.

-1=7/2(-4)+b

Solve for b.

-1=-28/2+b

-1=-14+b

13=b

y=7/2x+13

3 0

3 years ago

I need help once more (●'◡'●)

Luden [163]

Answer:

3= 25 4= 20 25= 5

Step-by-step explanation:

its a pattern. the top goes up by ones and the bottom goes up by fives.

7 0

2 years ago

The school principal wants to order 2 pencils for the 425 students in the school. How many boxes should she order?

olganol [36]

How many pencils are in each box

5 0

2 years ago

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2,45,250 students appeared for an entrance examination. If 94,750 students did not get admission, find how many students got adm

Lorico [155]

Answer:

2.45.250- 94.750

= 92. 2975. this is the learners who got the admission

6 0

2 years ago

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