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pickupchik [31]
3 years ago
13

Five liters of water were poured from tank A into tank B. and ten liters of water were then poured into tank C. If tank A origin

ally had 10 more liters of water than tank C, how many more liters of water does tank C now have than tank A?
Mathematics
2 answers:
Olegator [25]3 years ago
8 0

Answer:

It would be 5 liters because you gave 5 liter to C

Step-by-step explanation:

Hope this helped! :3

Nat2105 [25]3 years ago
3 0

Answer:

Step-by-step explanation:It has 5 more liters because it was transferred to tank C.

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Mr. Aba builds a circular patio with a diameter of 12 feet. He covers the patio with paving stones. The cost of the paving stone
Anettt [7]

Answer:

395.85

Step-by-step explanation:

If the diameter is 12, then the radius must be 6. Following the formula of pi: 2 * pi * radius, our result is 37.7. 37.7 * 10.50 is 395.85

I really hope this helps. My memory of circles and pi isn't the best.

8 0
2 years ago
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If f(x)= 5x, what is f^-1(x)?
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Step-by-step explanation:

f( x) {}^{ - 1}  \\ f(x) = 5x \\ y = 5x \\ x = 5y \\ y =  \frac{x}{5}  \\ f(x) {}^{ - 1}  =  \frac{x}{5}

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2 years ago
The function h(t)=-4.92t^2+17.69t+575 is used to model an object being tossed from a tall building, where h(t) is the height in
nikklg [1K]
We have the following equation:
<span> h(t)=-4.92t^2+17.69t+575

</span> For the domain we have:
<span> </span>We match zero:
 -4.92t ^ 2 + 17.69t + 575 = 0
 We look for the roots:
 t1 = -9.16
 t2 = 12.76
 We are left with the positive root, so the domain is:
 [0, 12.76]

 For the range we have:
 We derive the function:
 h '(t) = - 9.84t + 17.69
 We equal zero and clear t:
 -9.84t + 17.69 = 0
 t = 17.69 / 9.84
 t = 1.80
 We evaluate the time in which it reaches the maximum height in the function:
 h (1.80) = - 4.92 * (1.80) ^ 2 + 17.69 * (1.80) +575
 h (1.80) = 590.90
 Therefore, the range is given by:
 [0, 590.9]

 Answer:
 the domain and range are:
 
domain: [0, 12.76] range: [0, 590.9]
5 0
3 years ago
Read 2 more answers
Find the graph and all the characteristics (centre,vertex,covertice,length of
katen-ka-za [31]

8x²+3y²=24

8x²+3y²-24=0

Let x be 1 ,

Therefore

8+3y²-24=0

3y²-16=0

3y²=16

y²=16/3

y=4/1.7

y=40/17

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8 0
3 years ago
On a standard reticulocyte preparation with new methylene blue, there are 100 cells counted with blue-stained granulofilamentous
DIA [1.3K]

Answer:

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Step-by-step explanation:

Data provided in the question:

Number of cells counted with blue-stained granulofilamentous material

i.e number of RET = 100

The red blood cells count = 3.22 × 10¹² /L

Hematocrit = 30%

Now,

RET% = [ [ Number of RET ] ÷ 1000 RBCs ] × 100%

= [ 100 ÷ 1000 ] × 100%

= 0.1 × 100%

= 10%

also,

Absolute reticulocyte count = ( %RET × RBC count ) ÷ 100

= [ 10 × 3.22 × 10¹² /L ] ÷ 100

= 0.322 × 10¹² /L

8 0
3 years ago
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