C. would be the correct device to use in trials.
But the actual probability is:
(1-1/4)^5
243/1024
(about 23.73% chance none of the five chose vanilla)
Answer:
F(x) and h(x)
Step-by-step explanation:
f(x) has a high of three and so does H(x), g(x) has a high of -2 so it doesn't count
Katia and Thomasina play a computer game and record these scores. Katia: 8, 6, -4, -7, 2, 0, 3 Thomasina: -11, 0, 8, 7, 5, -7, 1
suter [353]
Answer:
Step-by-step explanation:
there is no factorization of y^2 -2y +35 in real numbers
Thomasina correctly determined two factors of 35 that differ by 2, but that is not what is needed here. For this problem, she needs two factors of 35 that have a sum of 2.* (There aren't any real-number factors that meet that condition.)
__
The factorization in complex numbers would be ...
= (y -1 -i√34)(y -1 +i√34)
_____
* Technically, she needs two factors of 35 with a sum of -2. Both factors would have to be negative.
Answer:
alternate angle, opposite angles are the same, 3x-3 = 147
x = 144/3 , x =48
Step-by-step explanation:
Let's assume that the statement "if n^2 is odd, then is odd" is false. That would mean "n^2 is odd" leads to "n is even"
Suppose n is even. That means n = 2k where k is any integer.
Square both sides
n = 2k
n^2 = (2k)^2
n^2 = 4k^2
n^2 = 2*(2k^2)
The expression 2(2k^2) is in the form 2m where m is an integer (m = 2k^2) which shows us that n^2 is also even.
So this contradicts the initial statement which forces n to be odd.
