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3 years ago

Please help me or tell me the answer

Mathematics

1 answer:

arsen [322]3 years ago

7 0

B and F because they would be multiplied by 100, which would move the digits two times to the right.

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Plz help! It's another probability question! Whoever answers correctly gets marked as brainliest!

Gelneren [198K]

Answer:

this is what I found:

Step-by-step explanation:

mark brainliest please :)

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4 years ago

Someone tell me what is x/3=33? I'm in 7th grade so I'm not in the hard algebra yet.

navik [9.2K]

To get rid of the 3, you multiply the x/3 by 3 to get x by itself. But if you multiply one side you have to multiply the other. So x = 99

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4 years ago

6x+12 factorizar mediante a factor comun<br>

Art [367]

6(x+2)
you just factor 6 from the expression
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3 years ago

Tasha eats half her snack and gives the other half to two of her best friends to share equally. What portion of the whole snack

dybincka [34]

Answer:

tasha got 1/2 of it

one friend got 1/4 of it

the other friend got 1/4 of it

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie

allsm [11]

Answer:

<em>The building is 61.5 m tall</em>

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

h = height of the building

a, b = internal angles of each triangle

x = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

$\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}$

$\displaystyle \tan 53^\circ=\frac{150-x}{h}$

$\displaystyle \tan 48^\circ=\frac{x}{h}$

From the last equation:

$x=h.\tan 48^\circ$

Substituting into the first equation:

$\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}$

Operating on the right side:

$\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ$

Rearranging:

$\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}$

Solving for h:

$\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}$

Calculating:

h = 61.5 m

The building is 61.5 m tall

5 0

3 years ago