J:V = 3:2
3:2 x 40 = 120:80
J: 120-15 = 105
V: 80+15 = 95
J:V is now 105:95
The original amount of peas that Julia had at first was 120.
Answer:
We have the function:
r = -3 + 4*cos(θ)
And we want to find the value of θ where we have the maximum value of r.
For this, we can see that the cosine function has a positive coeficient, so when the cosine function has a maximum, also does the value of r.
We know that the meaximum value of the cosine is 1, and it happens when:
θ = 2n*pi, for any integer value of n.
Then the answer is θ = 2n*pi, in this point we have:
r = -3 + 4*cos (2n*pi) = -3 + 4 = 1
The maximum value of r is 7
(while you may have a biger, in magnitude, value for r if you select the negative solutions for the cosine, you need to remember that the radius must be always a positive number)
<span><span><span>1/2</span><span>(<span><span>2g</span>−3</span>)</span></span>=<span>−<span>4<span>(<span>g+1</span>)</span></span></span></span>
<span><span><span>1/2</span><span>(<span><span>2g</span>−3</span>)</span></span>=<span>−<span>4<span>(<span>g+1</span>)</span></span></span></span>
<span><span>g+<span><span>−3/</span>2</span></span>=<span><span>−<span>4g</span></span>−4</span></span>
<span><span><span>g+<span><span>−3/</span>2</span></span>+<span>4g</span></span>=<span><span><span>−<span>4g</span></span>−4</span>+<span>4g</span></span></span><span><span><span>5g</span>+<span><span>−3</span>2</span></span>=<span>−4</span></span>
5g+−3/2+3/2=−4+3/2
<span><span>
5g</span>=<span><span>−5/</span>2</span></span>
<span><span><span>5g/</span>5</span>=<span><span><span>−5</span>2</span>5</span></span><span>
g=<span><span>−1</span><span>2
Hoped I helped!</span></span></span>
Answer:
Step-by-step explanation:
Your right I think it's c
