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2 years ago

There are ____________ kilobytes in an exabyte 230 220 240 250

Mathematics

2 answers:

Papessa [141]2 years ago

6 0

There are approximately 1125899906842618 kilobytes in an exabyte...

olga_2 [115]2 years ago

6 0

Answer:

Step-by-step explanation:

i took the test and got it correct

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The following dot plot represents a random sample of elementary students and the number of children that live in their home.

NISA [10]

None of the households in the United States contain five children.

The majority of the households in the United States, with at least one child, contain less than three children.

If thats wrong dont go off on me

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2 years ago

Todd swam 2/8 of a mile. Jerry swam 5/6 of a mile. Which boy swam further?

Alinara [238K]

Answer:

Jerry swam further then todd

Step-by-step explanation:

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1 year ago

20k + 5 = 5k + 65 know the answer

Katyanochek1 [597]

Solving for 'k'

20k + 5 = 5k + 65

20k = 5k + 65 -5

20k = 5k + 60

20k - 5k = 60

15k = 60

15k/15 = 60/15

k = 4

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2 years ago

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I have to do Decompose fractions and my problem is 3 over 7 what do I do?

mart [117]

Just simplify them to a decimal by dividing the numerator by the denominator.

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2 years ago

P³ = 1/8 please help me if anybody can .

ivanzaharov [21]

Answer:

$p= \dfrac{1}{2}$

Step-by-step explanation:

Given equation:

$p^3=\dfrac{1}{8}$

Cube root both sides:

$\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}$

$\implies p= \sqrt[3]{\dfrac{1}{8}}$

$\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:$

$\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}$

$\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:$

$\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}$

$\textsf{Apply exponent rule} \quad 1^a=1:$

$\implies p= \dfrac{1}{8^{\frac{1}{3}}}$

Rewrite 8 as 2³:

$\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}$

$\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:$

$\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}$

Simplify:

$\implies p= \dfrac{1}{2^{\frac{3}{3}}}$

$\implies p= \dfrac{1}{2^{1}}$

$\implies p= \dfrac{1}{2}$

3 0

7 months ago

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