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nikklg [1K]
3 years ago
11

I need help with this problem

Mathematics
1 answer:
-BARSIC- [3]3 years ago
6 0
Regular is
$97.99 after sale price is 83.30
97.99- 83.30= 14.69 is the discount
You can do it same way with B C and D
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Hi help please and thank you ​
Charra [1.4K]

Answer:

looks hard

Step-by-step explanation:

6 0
3 years ago
Students conducted a survey to see which cola was preferred most. People preferred cola A to cola B by a ratio of 9:7. If 108 pe
tigry1 [53]

Answer:

c:84

Step-by-step explanation:

set your equasion to 9/7 = 108/x .solve the equasion and you get 84 for x

4 0
3 years ago
How do you write 4.04bas a percent?
user100 [1]
It would be 404%

Hope this helps!
6 0
2 years ago
Use these clues to guess the mystery number. It is an odd number. It is greater than 142. It is less than 156. Rounded to the ne
Marianna [84]
Could be 154. 154 rounded to nearest ten= 150, rounded to nearest 100= 200
8 0
3 years ago
Read 2 more answers
In an effort to estimate the mean of amount spent per customer for dinner at a major Lawrence restaurant, data were collected fo
larisa86 [58]

Answer:

The 99% confidence interval for the population mean is 22.96 to 26.64

Step-by-step explanation:

Consider the provided information,

A sample of 49 customers. Assume a population standard deviation of $5. If the sample mean is $24.80,

The confidence interval if 99%.

Thus, 1-α=0.99

α=0.01

Now we need to determine z_{\frac{\alpha}{2}}=z_{0.005}

Now by using z score table we find that  z_{\frac{\alpha}{2}}=2.58

The boundaries of the confidence interval are:

\mu-z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80-2.58\times \frac{5}{\sqrt{49}}=22.96\\\mu+z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80+2.58\times \frac{5}{\sqrt{49}}=26.64

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64

3 0
3 years ago
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