To find the inverse,
First, you would have to switch the domain and range. In other words, swap x and y:
h(x) = 3/ -x-2
y = 3/ -x-2
x = 3/ -y-2
Then, when you have this, simply solve for y:
x = 3/-y-2
x (-y-2) = 3/-y-2 (-y-2)
x(-y-2) /x= 3 /x
-y-2 = 3/x
-y = 3/x + 2
y = -3/x -2
So the inverse would be
h⁻¹(x)= -3/x -2
Supplementary angles have a degree measure of 180, so they look like a straight line.
Your answers are 4 and 3, 4 and 5, and 3 and 6.
Let x =lenght, y = width, and z =height
<span>The volume of the box is equal to V = xyz </span>
<span>Subject to the surface area </span>
<span>S = 2xy + 2xz + 2yz = 64 </span>
<span>= 2(xy + xz + yz) </span>
<span>= 2[xy + x(64/xy) + y(64/xy)] </span>
<span>S(x,y)= 2(xy + 64/y + 64/x) </span>
<span>Then </span>
<span>Mx(x, y) = y = 64/x^2 </span>
<span>My(x, y) = x = 64/y^2 </span>
<span>y^2 = 64/x </span>
<span>(64/x^2)^2 = 64 </span>
<span>4096/x^4 = 64/x </span>
<span>x^3 = 4096/64 </span>
<span>x^3 = 64 </span>
<span>x = 4 </span>
<span>y = 64/x^2 </span>
<span>y = 4 </span>
<span>z= 64/yx </span>
<span>z= 64/16 </span>
<span>z = 4 </span>
<span>Therefor the dimensions are cube 4.</span>
What is the arithmetic mean of the following numbers? 3, 5, 6, 7, 9, 6, 83,5,6,7,9,6,8
liubo4ka [24]
Answer:
oh wow that's giving me a headache, I dont understand
