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WITCHER [35]
3 years ago
8

write a compound inequality that represents the situation. all real numbers at least –6 and at most 3 a. –6 < x ≤ 3 b. –6 &lt

; x < 3 c. –6 ≤ x ≤ 3 d. –6 ≥ x ≥ 3
Mathematics
2 answers:
kotegsom [21]3 years ago
8 0
<span>All real numbers at least –6 and at most 3 is given by: -6 \leq x \leq 3</span>
mamaluj [8]3 years ago
3 0

Answer: c. –6 ≤ x ≤ 3


Step-by-step explanation:

Given situation: All real numbers at least –6 and at most 3.

Let x be a real number

and "at least" means the minimum value , so 'x' must b greater than or equal to the minimum value i.e. –6 ≤ x .

"at most" means the maximum value , so 'x' must be smaller than or equal to the maximum value i.e. x ≤ 3 .

then according to the given situation,

All real numbers at least –6 and at most 3.

⇒ –6 ≤ x ≤ 3

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Step-by-step explanation:

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At a road race, you have 60 3/4 feet available for a water station. Your tables are 6 3/4 feet long. How many tables can you lin
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8 0
3 years ago
The proportion of students at a college who have GPA higher than 3.5 is 19%. a. You take repeated random samples of size 25 from
melomori [17]

Answer:

\mu_{\hat{p}}=0.19

\sigma_{\hat{p}}=0.0785

Step-by-step explanation:

We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-

\mu_{\hat{p}}=p

\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}

, where p=population proportion and n= sample size.

Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.

i.e. p= 19%=0.19

The for sample size n= 25

The mean and the standard error of the sampling distribution of the sample proportions will be :-

\mu_{\hat{p}}=0.19

\sigma_{\hat{p}}=\sqrt{\dfrac{0.19(1-0.19)}{25}}\\\\=\sqrt{0.006156}=0.0784601809837\approx0.0785

Hence , the mean and the standard error of the sampling distribution of the sample proportions :

\mu_{\hat{p}}=0.19

\sigma_{\hat{p}}=0.0785

8 0
3 years ago
50× 3/8 how to reduce answer to lowest te
hoa [83]

The lowest term is \frac{75}{4}.

Solution:

Given expression is 50\times\frac{3}{8}

<u>To reduce this term to the lowest term:</u>

$50\times\frac{3}{8}=\frac{50}{1}\times\frac{3}{8}

Multiply the numerator and denominator.

$50\times\frac{3}{8}=\frac{150}{8}

Now, divide the numerator and denominator by the greatest common factor.

Here 150 and 8 both have common factor 2.

So, divide numerator and denominator by 2.

           $=\frac{150\div2}{8\div2}

           $=\frac{75}{4}

$50\times\frac{3}{8}=\frac{75}{4}

Hence the lowest term is \frac{75}{4}.

4 0
3 years ago
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