After adding 8 students to each of 6 same-sized teams, there were 72 students altogether.
After adding an 8-pound box of tennis rackets to a crate with 6 identical boxes of ping pong paddles, the crate weighed 72 pounds.
The first situation has all equal parts, since additions are made to each team. An equation that represents this situation is 6( x + 8 ) = 72, where x represents the original number of students on each team. Eight students were added to each group, there are 6 groups, and there are a total of 72 students.
In the second situation, there are 6 equal parts added to one other part. An equation that represents this situation is 6x + 8 = 72, where x represents the weight of a box of ping pong paddles, there are 6 boxes of ping pong paddles, there is an additional box that weighs 8 pounds, and the crate weighs 72 pounds altogether.
In the first situation, there were 6 equal groups, and 8 students added to each group. 6( x + 8 ) = 72.
In the second situation, there were 6 equal groups, but 8 more pounds in addition to that. 6x + 8 = 72.
We have been given the expression
We have the exponent rule
Using this rule, we have
Now, using the fact that ![x^{\frac{1}{n}}=\sqrt[n]{x}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%7D)
, we get
![x^{\frac{9}{7}}= \sqrt[7]{x^9}\\ \\ x^{\frac{9}{7}}=\sqrt[7]{x^7\times x^2}\\ \\ x^{\frac{9}{7}}=x\sqrt[7]{x^2}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B9%7D%7B7%7D%7D%3D%20%5Csqrt%5B7%5D%7Bx%5E9%7D%5C%5C%0A%5C%5C%0Ax%5E%7B%5Cfrac%7B9%7D%7B7%7D%7D%3D%5Csqrt%5B7%5D%7Bx%5E7%5Ctimes%20x%5E2%7D%5C%5C%0A%5C%5C%0Ax%5E%7B%5Cfrac%7B9%7D%7B7%7D%7D%3Dx%5Csqrt%5B7%5D%7Bx%5E2%7D)
D is the correct option.
Answer:
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Answer:
Step-by-step explanation:
The average rate of change can be found by using the following formula
Since the interval goes from -7 to 2, we should find the y-values that correspond to x=-7 and x=2.
By inspection of the graph, we can clearly see that when x is -7, y is -7 as well and when x is 2, y is 5.
Now that we know this, we can simply plug these values into the formula!
Good luck!
