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3 years ago

Anyone help me solve this? And show work please

Mathematics

1 answer:

inessss [21]3 years ago

4 0

Answer:

A) 2a + 6

Step-by-step explanation:

(5a + 3) + (2a + 3) + x = 9a + 12

Add both side lengths plus the unknown side to equal the perimeter.

7a + 6 + x = 9a + 12

-7a -6 -7a -6 Subtract 7a + 6 on both sides

x = 2a + 6 This is the missing side length.

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Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

2 years ago

X2 + y when x = -2 and y = 3.

OlgaM077 [116]

(-2)2+3= -1 hope this helps you

6 0

2 years ago

Read 2 more answers

Question is in image below.

inysia [295]

Answer:

a=2/3

Step-by-step explanation:

4/3 divide by 2/3 and you get 2/3

5 0

3 years ago

A trapezoid is broken into 2 triangles and 1 rectangle. The triangles both have a base of 2 meters and a height of 5 meters. The

Lemur [1.5K]

Answer:

Part 1) The trapezoid has an area of $20\ m^2$

Part 2) The kite has an area of $21\ m^2$

Part 3) The area of the trapezoid is less than the area of the kite

Step-by-step explanation:

Part 1

Find the area of trapezoid

we know that

The area of trapezoid is equal to the area of two congruent triangles plus the area of a rectangle

$A=2[\frac{1}{2} (2)(5)]+(2)(5)$

$A=10+10=20\ m^2$

Part 2

Find the area of the kite

we know that

The area of the kite is equal to the area of two congruent triangles

$A=2[\frac{1}{2} (7)(3)]=21\ m^2$

Part 3

Compare the areas

The trapezoid has an area of $20\ m^2$

The kite has an area of $21\ m^2$

$20\ m^2< 21\ m^2$

therefore

The area of the trapezoid is less than the area of the kite

5 0

3 years ago

Read 2 more answers

Someone help :(( thank youuuu so much if u do

VMariaS [17]

Answer:

-10

Step-by-step explanation:

The equation would be -8 - (-10) = 2. When subtracting a negative, you are actually just adding a positive. It's like the two negative signs cancel each other out, so it would look more like -8 + 10 = 2. For the answer box, just put -10.

5 0

2 years ago