Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to

sq. units.
16--(3) $17
17--(3) $64
18--(2) $18
Answer:
x + 2
Step-by-step explanation:
If we know one of the factors, we should be able to use long division.
We can divide the trinomial by the binomial and find the other factor.
<u>x + 2</u><u> </u>
x² + 4x + 3)x³ + 6x² + 11x + 6
<u>x³ + 4x² + 3x</u>
2x² + 8x + 6
<u>2x² + 8x + 6</u>
0
Thus,

Answer: x=-63/73
Step-by-step explanation:
Multiply both sides by 12, Move constant to the right hand side and change its sign, Move variable to the left hand side and change its sign, collect like terms, divide both sides of the equation by -73, x=-63/73 (- 63 over 73)
-5x-10=10 x= -4
Work:
-5x-10=10
+10 +10
______________
-5x=20
_______
-5 -5
x=-4