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OLga [1]
3 years ago
15

If your income was ​$40 and the price of pizzas was ​$5 and the price of videos was ​$4​, what combination of pizzas and videos

would maximize your​ utility?
Mathematics
2 answers:
emmainna [20.7K]3 years ago
8 0

Answer: 4 pizzas and 5 videos

Step-by-step explanation:

Income= $40

Price of pizza= $5

Price of video= $4

Let pizza be represented as p

Let video be represented as v

5p + 4v = 40

Solving further, the amount of pizza and video that will maximize utility are 4 and 5 respectively.

valentina_108 [34]3 years ago
7 0

Answer:

4 pizza and 4 videos

Step-by-step explanation:

let p represent the number of pizza

let v represent the number of videos

Total income = $40

Price of pizza = $5

Price of video = $4

Price of pizza and video = $5 + $4

= $9

Total amount spent on pizza = (5/9)* 40

= 200/9 = $22.22

Total number of pizza bought = 22.22/5 = 4.4

= 4 pizza(approximately)

Total amount spent on video = (4/9)*40 = 160/9

= 17.77

Total number of videos = 17.77/4 = 4.44 = 4 videos (approximately)

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The function y = (x - 4)2 + 3 is a transformation of the function y = x?. How is the function's vertex affected by the
slava [35]

Answer:

The vertex of the graph of y = x is shifted to the right 3 units and up 4 units.

The vertex of the graph of y = x?is shifted to the right 4 units and up 3 units.

3 0
3 years ago
Are the these expressions equivalent 6a + 12 and 3(3a + 4)
kow [346]

Answer:

No

Step-by-step explanation:

6a + 12  =? 3(3a + 4)

Distribute

6a+12 =? 3*3a + 3*4

6a+12 =? 9a +12

No

The expressions are not equivalent

5 0
3 years ago
Read 2 more answers
Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
3 years ago
Help please due now
umka21 [38]

Answer:

hii here is your answer

6 0
3 years ago
Please help me fast and show all your work please thx ​
Kitty [74]

If the two diagonals are d and D, the are of the rhombus is

A=\dfrac{dD}{2}

So, in your case, the area is

A=\dfrac{15\cdot 35}{2}=262.5

The other options are wrong because:

  • option A doens't divide by 2, thus getting twice the area of the rhombus
  • option B summed the diagonals instead of multiplying them
  • option D took the difference of the diagonals.
8 0
3 years ago
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