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2 years ago

Write 12 3/20 as a decimal number

Mathematics

2 answers:

never [62]2 years ago

5 0

Answer:

12.15

Step-by-step explanation:

3/20 = 15/100 = 0.15

Explanation:

Decimals are way of writing fractions which have denominators that are powers of 10

0.3 = 3/10

0.38 = 38/100

0.384 = 384/1000

etc

Find an equivalent fraction for 3/20

3/20× 5/5 = 15/ 100

This can now be written as

0.15

and the remaining whole twelve you are to add

so it would be 12.15

shepuryov [24]2 years ago

3 0

Answer:

12.15

Step-by-step explanation:

It is 12.15 because you have 12, right? 3 divided by 20, gives you 15.

Another way you can use to find the answer is taking 3/20 from 12 3/20, and then 3/20 equals 15/100. As a decimal it will be 12.15

Hope this helps!

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Two students in your class, Tucker and Karly, are disputing a function. Tucker says that for the function, between x = –3 and x

Effectus [21]

The difference between Tucker and Karly's take is that Tucker's solution is analytical while Karly's is graphical. But both are correct either way.

For Tucker's solution, let's say at x=-3 the value for y is 4, and at x=3, the value of y is still 4, then the average rate of change or slope is 0. Note that the slope of the curve is Δy/Δx. Since there is no change for Δy, the slope is zero.

For Karly's solution, even if the curve travels high or low but would have the same elevation of x=-3 and x=3, the average rate of change is still zero. It is actually just same with Tucker's but Karly just verbalizes her solution that was observed visually.

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2 years ago

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}$

Apply the <u>zero-product property</u> and solve for x:

$\implies x+1=0 \implies x=-1$

$\implies x-5=0 \implies x=5$

Substitute the found values of x into the <u>second equation</u> and solve for y:

$\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}$

$\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}$

Therefore, the solutions are:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

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MaRussiya [10]

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2 years ago

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Ivenika [448]

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quester [9]

Answer:

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Step-by-step explanation:

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