Answer:
<h2><u>b = 2 or b = -2</u></h2>
Explanation:
|4b + 4| = |2b + 8|
<em>Solve absolute value</em>
|4b + 4| = |2b + 8|
Either 4b + 4 = 2b + 8 or 4b + 4 = −(2b + 8)
4b + 4 = 2b + 8 <em>(Possibility 1)</em>
4b + 4 − 2b = 2b + 8 − 2b <em>(Subtract 2b from both sides)</em>
2b + 4 = 8
2b + 4 − 4 = 8 − 4 <em>(Subtract 4 from both sides)</em>
2b = 4
2b / 2 = 4 / 2 <em>(Divide both sides by 2)</em>
b = 2
4b + 4 = −(2b + 8) <em>(Possibility 2)</em>
4b + 4 = −2b − 8 <em>(Simplify both sides of the equation)</em>
4b + 4 + 2b = −2b − 8 + 2b <em>(Add 2b to both sides)</em>
6b + 4 = −8
6b + 4 − 4 = −8 − 4 <em>(Subtract 4 from both sides)</em>
6b = −12
6b / 6 = -12 / 6 <em>(Divide both sides by 6)</em>
b = -2
<h2><u>b = 2 or b = -2</u></h2>
Since you have the answers given, just track their walking.
After one hour, one guy has covered 3mi and the other 4mi, which is in total 7, not 14
After 2 hours, one guy has covered 6mi and the other 8mi, which is 14mi
The algebraic way would be:
3x +4x = 14 *x being the hour
7x = 14
x =2
Answer:
Complete the following statements. In general, 50% of the values in a data set lie at or below the median. 75% of the values in a data set lie at or below the third quartile (Q3). If a sample consists of 500 test scores, of them 0.5*500 = 250 would be at or below the median. If a sample consists of 500 test scores, of them 0.75*500 = 375 would be at or above the first quartile (Q1).
Step-by-step explanation:
The median separates the upper half from the lower half of a set. So 50% of the values in a data set lie at or below the median, and 50% lie at or above the median.
The first quartile(Q1) separates the lower 25% from the upper 75% of a set. So 25% of the values in a data set lie at or below the first quartile, and 75% of the values in a data set lie at or above the first quartile.
The third quartile(Q3) separates the lower 75% from the upper 25% of a set. So 75% of the values in a data set lie at or below the third quartile, and 25% of the values in a data set lie at or the third quartile.
The answer is:
Complete the following statements. In general, 50% of the values in a data set lie at or below the median. 75% of the values in a data set lie at or below the third quartile (Q3). If a sample consists of 500 test scores, of them 0.5*500 = 250 would be at or below the median. If a sample consists of 500 test scores, of them 0.75*500 = 375 would be at or above the first quartile (Q1).
Answer:
3x^2 + 12x + 4y^2 - 8y = 32
Step-by-step explanation:
3(x^2+4x)+4(y^2-2y)=32
At first we have to break the parenthesis to get the variables in normal position. To break those, we have to multiply each with the help of algebraic expression:
or, (3*x^2) + (3 × 4x) + (4 × y^2) - (4 × 2y) = 32
or, 3x^2 + 12x + 4y^2 - 8y = 32
Since the equation does not have anything to add or deduct, therefore, it is the answer.
Answer:
D:3
Step-by-step explanation:
