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BigorU [14]
3 years ago
8

How do you do this question?

Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Answer:

33/16

Step-by-step explanation:

x = y⁴/8 + 1/(4y²), 1 ≤ y ≤ 2

dx/dy = y³/2 − 1/(2y³)

Arc length is:

s = ∫ ds

s = ∫ √(1 + (dx/dy)²) dy

s = ∫₁² √(1 + (y³/2 − 1/(2y³))²) dy

s = ∫₁² √(1 + y⁶/4 − ½ + 1/(4y⁶)) dy

s = ∫₁² √(½ + y⁶/4 + 1/(4y⁶)) dy

s = ∫₁² ½ √(2 + y⁶ + 1/y⁶) dy

s = ∫₁² ½ √(y³ + 1/y³)² dy

s = ∫₁² ½ (y³ + 1/y³) dy

s = ½ (y⁴/4 − 1/(2y²)) |₁²

s = ½ (16/4 − 1/8) − ½ (1/4 − 1/2)

s = 33/16

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lapo4ka [179]

Hey!

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Steps To Solve:

17 - 2v = -53

~Subtract 17 to both sides

17 - 2v - 17 = -53 - 17

~Simplify

-2v = -70

~Divide 2 to both sides

-2v/-2 = -70/-2

~Simplify

v = 35

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Hence, the answer is \Large\boxed{\mathsf{v~=~35}}

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Hope This Helped! Good Luck!

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Plot the solution on the number line.

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