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BigorU [14]
3 years ago
8

How do you do this question?

Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Answer:

33/16

Step-by-step explanation:

x = y⁴/8 + 1/(4y²), 1 ≤ y ≤ 2

dx/dy = y³/2 − 1/(2y³)

Arc length is:

s = ∫ ds

s = ∫ √(1 + (dx/dy)²) dy

s = ∫₁² √(1 + (y³/2 − 1/(2y³))²) dy

s = ∫₁² √(1 + y⁶/4 − ½ + 1/(4y⁶)) dy

s = ∫₁² √(½ + y⁶/4 + 1/(4y⁶)) dy

s = ∫₁² ½ √(2 + y⁶ + 1/y⁶) dy

s = ∫₁² ½ √(y³ + 1/y³)² dy

s = ∫₁² ½ (y³ + 1/y³) dy

s = ½ (y⁴/4 − 1/(2y²)) |₁²

s = ½ (16/4 − 1/8) − ½ (1/4 − 1/2)

s = 33/16

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3 years ago
A bibliophile plans to put a total of seven books on her marble shelf. She can choose these seven books from a mixture of works
Tcecarenko [31]

Answer:

1715

Step-by-step explanation:

GIVEN: A bibliophile plans to put a total of seven books on her marble shelf. She can choose these seven books from a mixture of works from Antiquity and works on Post-modernism, of which there are seven each.

TO FIND: If the shelf must contain at least four works from Antiquity, and one on Post-Modernism, then how many ways can he select seven books to go on the shelf.

SOLUTION:

Total number of books available =14

As there must be at least 4 books on  Antiquity and 1 on Post-modernism

Therefore,

when there are 6 Antiquity books and 1 on Post-modernism.

total ways of selection =^7C_6\times^7C_1=49

when there are 5 Antiquity books and 2 on Post-modernism.

total ways of selection =^7C_5\times^7C_2=21\times21

                                                          =441

when there are 4 Antiquity books on 3 books on Post-modernism.

total ways of selection =^7C4\times^7C3=35\times35

                                                           =1225

Total ways of selection are =1225+441+49

                                             =1715

Hence the total ways of selection such that there are at least 4 books on  Antiquity and 1 on Post-modernism.

6 0
3 years ago
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